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Veronika [31]
2 years ago
15

Which statements are true?

Mathematics
1 answer:
gtnhenbr [62]2 years ago
7 0

All triangles are polygons, have 3 straight sides, and are closed figures. Then the correct options are A, B, and E.

<h3>What is the triangle?</h3>

A triangle is a three-sided polygon with three angles. The angles of the triangle add up to 180 degrees.

The true statements are given below.

  • All triangles are polygons.
  • All triangles have 3 straight sides.
  • All triangles are closed figures.

Then the correct options are A, B, and E.

More about the triangle link is given below.

brainly.com/question/25813512

#SPJ1

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Help!!! I don’t understand how to do this
lidiya [134]

Answer:

  f^{(k)}(x)=\dfrac{17k!(-1)^k}{(x-9)^{k+1}}

Step-by-step explanation:

The question presumes you have access to a computer algebra system. The one I have access to provided the output in the attachment. The list at the bottom is the list of the first four derivatives of f(x).

__

The derivatives alternate signs, so (-1)^k will be a factor.

The numerators start at 17 and increase by increasing factors: 2, 3, 4, indicating k! will be a factor.

The denominators have a degree that is k+1.

Putting these observations together, we can write an expression for the k-th derivative of f(x):

  \boxed{f^{(k)}(x)=\dfrac{17k!(-1)^k}{(x-9)^{k+1}}}

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3 years ago
Use the algebraic procedure explained in section 8.9 in your book to find the derivative of f(x)=1/x. Use h for the small number
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Answer:

By definition, the derivative of f(x) is

lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}

Let's use the definition for f(x)=\frac{1}{x}

lim_{h\rightarrow 0} \frac{\frac{1}{x+h}-\frac{1}{x}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{x-(x+h)}{x(x+h)}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{(-1)h}{x^2+xh}}{h}=\\lim_{h\rightarrow 0} \frac{(-1)h}{h(x^2+xh)}=\\lim_{h\rightarrow 0} \frac{-1}{x^2+xh)}=\frac{-1}{x^2+x*0}=\frac{-1}{x^2}

Then, f'(x)=\frac{-1}{x^2}

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