It is easier to do if we get rid of the decimals, so lets multiply both numbers by 10:
5.8/1.2 = 58/12
and reduce the fraction:
= 29/6
then operate:
= 4.83
Answer:
Δ JKL is similar to Δ ABC ⇒ D
Step-by-step explanation:
Similar triangles have equal angles in measures
In ΔABC
∵ m∠A = 15°
∵ m∠B = 120
∵ The sum of the measures of the interior angles of a Δ is 180°
∴ m∠A + m∠B + m∠C = 180°
→ Substitute the measures of ∠A and ∠B
∵ 15 + 120 + m∠C = 180
→ Add the like terms in the left side
∴ 135 + m∠C = 180
→ Subtract 135 from both sides
∴ 135 - 135 + m∠C = 180 - 135
∴ m∠C = 45°
The similar Δ to ΔABC must have the same measures of angles
If triangles ABC and JKL are similar, then
m∠A must equal m∠J
m∠B must equal m∠K
m∠C must equal m∠L
∵ m∠J = 15°
∴ m∠A = m∠J
∵ m∠L = 45°
∴ m∠C = m∠L
∵ m∠J + m∠K + m∠L = 180°
→ Substitute the measures of ∠J and ∠L
∵ 15 + m∠K + 45 = 180
→ Add the like terms in the left side
∴ 60 + m∠K = 180
→ Subtract 60 from both sides
∴ 60 - 60 + m∠K = 180 - 60
∴ m∠K = 120°
∴ m∠B = m∠K
∴ Δ JKL is similar to Δ ABC
Answer:
B) a = 6.7, B = 36°, C = 49°
Step-by-step explanation:
Fill in the numbers in the Law of Cosines formula to find the value of "a".
a² = b² + c² -2bc·cos(A)
a² = 4² +5² -2(4)(5)cos(95°) ≈ 44.4862
a ≈ √44.4862 ≈ 6.66980
Now, the law of sines is used to find one of the remaining angles. The larger angle will be found from ...
sin(C)/c = sin(A)/a
sin(C) = (c/a)sin(A)
C = arcsin(5/6.6698×sin(95°)) ≈ 48.31°
The third angle is ...
B = 180° -A -C = 180° -95° -48.31° = 36.69°
The closest match to a = 6.7, B = 37°, C = 48° is answer choice B.
13) B. 8.47,8.67,8.7
14) A
Just ask for explanation if u need it
Hope that helped :)
