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Mandarinka [93]
3 years ago
13

I am struggling hard out with linear algebra in math level one

Mathematics
1 answer:
Elena L [17]3 years ago
4 0
I would recommend "Introduction to Linear Algebra," by Gilbert Strang. It is a compact but very helpful textbook reference written by a well-known MIT professor. There is a corresponding online MIT course that is free, so that's a bonus. I am currently using it to study linear algebra with no class or previous experience, and I think it does a solid job of explaining things. Each section in the book has a set of questions for you to work through, and answers to selected questions appear in an appendix at the end of the book. Hope this helps!
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PLEASE HELP!!!!
pogonyaev

Answer:

30.667, in 1 hour = 40 miles

Step-by-step explanation:

Set up a proportion so 1.5 miles / 2.25 minutes.

So 1.5/2.25 = x/46

solve for x 1.5(46)/2.25 = x so x = 30.667

In one hour is 60 minutes so  1.5(60)/2.25 = x

8 0
3 years ago
IS 250% of 44 over 100
Anna007 [38]

Answer:

Yes

Step-by-step explanation:

44 is 100%

100% + 100% + 50% = 250%

44 + 44 + 22 = More than 100

5 0
2 years ago
Read 2 more answers
Pls help asap math isn't my thing
stira [4]

Your answer is in the picture above

6 0
4 years ago
Help with 21 would be much appreciated.
umka2103 [35]

Answer:

\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

\dfrac{AD}{CD}=\dfrac{CD}{DB}

We have

AD=14-8=6\\CD=y\\DB=8

Substitute:

\dfrac{6}{y}=\dfrac{y}{8}         <em>cross multiply</em>

y^2=(6)(8)

y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}

For x use the Pythagorean theorem:

x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}

3 0
3 years ago
50 POINTS !!<br><br><br> PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.
Artyom0805 [142]

Answer:

12

Step-by-step explanation:

Use the pythagorean theorem (a^2+b^2=c^2). A and b are the two legs of the triangle, and c is ALWAYS the hypotenuse. Plug in the values for a and c

a^2+b^2=c^2

5^2+b^2=13^2

25+b^2=169

b^2=144

b=12

6 0
3 years ago
Read 2 more answers
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