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3 years ago

I am struggling hard out with linear algebra in math level one

1 answer:

4 0

I would recommend "Introduction to Linear Algebra," by Gilbert Strang. It is a compact but very helpful textbook reference written by a well-known MIT professor. There is a corresponding online MIT course that is free, so that's a bonus. I am currently using it to study linear algebra with no class or previous experience, and I think it does a solid job of explaining things. Each section in the book has a set of questions for you to work through, and answers to selected questions appear in an appendix at the end of the book. Hope this helps!

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PLEASE HELP!!!!

pogonyaev

Answer:

30.667, in 1 hour = 40 miles

Step-by-step explanation:

Set up a proportion so 1.5 miles / 2.25 minutes.

So 1.5/2.25 = x/46

solve for x 1.5(46)/2.25 = x so x = 30.667

In one hour is 60 minutes so 1.5(60)/2.25 = x

8 0

3 years ago

IS 250% of 44 over 100

Anna007 [38]

Answer:

Yes

Step-by-step explanation:

44 is 100%

100% + 100% + 50% = 250%

44 + 44 + 22 = More than 100

5 0

2 years ago

Read 2 more answers

Pls help asap math isn't my thing

stira [4]

Your answer is in the picture above

6 0

4 years ago

Help with 21 would be much appreciated.

umka2103 [35]

Answer:

$\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}$

Step-by-step explanation:

Look at the picture.

ΔADC and ΔCDB are similar. Therefore the sides are in proportion:

$\dfrac{AD}{CD}=\dfrac{CD}{DB}$

We have

$AD=14-8=6\\CD=y\\DB=8$

Substitute:

$\dfrac{6}{y}=\dfrac{y}{8}$ cross multiply

$y^2=(6)(8)$

$y^2=48\to y=\sqrt{48}\\\\y=\sqrt{16\cdot3}\\\\y=\sqrt{16}\ cdot\sqrt3\\\\\boxed{y=4\sqrt3}$

For x use the Pythagorean theorem:

$x^2=6^2+(4\sqrt3)^2\\\\x^2=36+48\\\\x^2=84\to x=\sqrt{84}\\\\x=\sqrt{4\cdot21}\\\\x=\sqrt4\cdot\sqrt{21}\\\\\boxed{x=2\sqrt{21}}$

3 0

3 years ago

50 POINTS !! PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.

Artyom0805 [142]

Answer:

Step-by-step explanation:

Use the pythagorean theorem ( $a^2+b^2=c^2$ ). A and b are the two legs of the triangle, and c is ALWAYS the hypotenuse. Plug in the values for a and c

$a^2+b^2=c^2$

$5^2+b^2=13^2$

$25+b^2=169$

$b^2=144$

$b=12$

6 0

3 years ago

Read 2 more answers