Answer:
14 (insert less than or equal symbol)8x+6
Hope this helps! i hope the symbol is right!
Answer:
D 14
Step-by-step explanation:
Let x be the number
2(x-4) = 20
Divide each side by 2
2/2(x-4) = 20/2
x-4 = 10
Add 4 to each side
x-4+4 = 10+4
x = 14
Answer:

Step-by-step explanation:
Given A = 5i + 11j – 2k and B = 4i + 7k, the vector projection of B unto a is expressed as 
b.a = (5i + 11j – 2k)*( 4i + 0j + 7k)
note that i.i = j.j = k.k =1
b.a = 5(4)+11(0)-2(7)
b.a = 20-14
b.a = 6
||a|| = √5²+11²+(-2)²
||a|| = √25+121+4
||a|| = √130
square both sides
||a||² = (√130)
||a||² = 130

<em>Hence the projection of b unto a is expressed as </em>
<em></em>
Answer:
414
Step-by-step explanation:
Answer:
You are going to take the shape and flip if across the x Axis, reversing it essentially. then you will move it up 4, so of it is a square with one corner at (2,3) it will go to (5, 7) and all the other point will move together if I remember right. I last did this 3 years ago, I hope I help, next time show the whole graph with the number and I would have put a visual to show you the answer. Good luck