Answer:
E
Step-by-step explanation:
We are given that a particle's position along the x-axis at time <em>t </em>is modeled by:

And we want to determine at which time(s) <em>t</em> is the particle at rest.
If the particle is at rest, this suggests that its velocity at that time is 0.
Since are we given the position function, we can differentiate it to find the velocity function.
So, by differentiating both sides with respect to <em>t</em>, we acquire:
![\displaystyle x^\prime(t)=v(t)=\frac{d}{dt}\big[2t^3-21t^2+72t-53\big]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%5E%5Cprime%28t%29%3Dv%28t%29%3D%5Cfrac%7Bd%7D%7Bdt%7D%5Cbig%5B2t%5E3-21t%5E2%2B72t-53%5Cbig%5D)
Differentiate. So, our velocity function is:

So, we will set the velocity to 0 and solve for <em>t</em>. Hence:

We can divide both sides by 6:

Factoring yields:

By the Zero Product Property:

Hence:

Therefore, at the 3rd and 4th seconds, the velocity of the particle is 0, impling that the particle is at rest.
Our answer is E.
Answer:
it's the square root of 63 and I'd assume rounding to the tenth but I dont know how ur teacher does it.
Step-by-step explanation:
find a calculator if u have one then solve for the square root of 63. this method is called the pythagorean theorem that i used
Think of the 13-ft length of the ladder as the hypotenuse of a right triangle. Represent the horiz. distance from foot of ladder to base of tree by x, or 5 ft.
Represent the vert. dist. from base of tree to top of ladder by y, which is unknown.
Then (13 ft)^2 = (5 ft)^2 + y^2, or
169 ft^2 = 25 ft^2 + y^2. This simplifies to y^2 = 144. Thus y = + 12 feeet.
Note: Please pay attention to your spelling: "lader i up agenst a tree" should be "the top of a 13-ft ladder is placed against a tree."
Answer:
1.) Not statistical
2.) Statistical
3.) Statistical.
Step-by-step explanation:
Statistical Statistical questions require collection of data and the answers have variability (there is more than 1 possible way to answer the question). Non-Statistical Non-Statistical questions have answers with no variability (there is only 1 answer).
If you need therapy or you're just bored, feel free to blow uf my notifications and spam in the comments. Or you can comment bcuz I got it wrong or something.