Answer:
{1,6}
Step-by-step explanation:
the second box is always where the y values/range are
Six hundred fifteen thousand and four
Answer what? This question? Oh, I'm answering it right now. Did you have another question out? Well, I can't see it.
You just need to solve for when 
:
where 
is any integer. We only care about when 
, which happens for 
.
(x + y)^2 = (x^2 - 2xy + y^2)
First distribute the ^2 on the left side of the equation to each term inside the parenthesis:
x^2+ 2xy + y^2
Now pick one of the variables to solve for and isolate it:
(solving for x)
x^2 + 2xy + y^2 = x^2 - 2xy + y^2
x^2+ 2xy = x^2 - 2xy
2xy = -2xy
-x = x
x = 0
When you solve for y in the equation it will turn out to be 0 as well
