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lbvjy [14]
2 years ago
14

Write the equation of an ellipse with center (-2,-3), vertical major axis of length 14, and minor axis of

Mathematics
1 answer:
Tems11 [23]2 years ago
5 0

Step-by-step explanation:

Since we have a vertical major axis, our ellipse is vertical.

The equation of a vertical ellipse is

\frac{(y - k) {}^{2} }{ {a}^{2} }  +  \frac{(x - h) {}^{2} }{ {b}^{2} }  = 1

where

(h,k) is the center

a is the semi major axis,

b is the semi minor axis

First, let plug in our center

\frac{(y + 3) {}^{2} }{ {a}^{2} }  + \frac{(x + 2) {}^{2} }{ {b}^{2} }  = 1

Semi means half, so

a is half of 14 which is 7

B is half of 8, which is 4.

\frac{(y + 3) {}^{2} }{49}  +  \frac{(x + 2) {}^{2} }{16}  = 1

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1) we solve this square equation:
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In this question (brainly.com/question/12792658) I derived the Taylor series for \mathrm{sinc}\,x about x=0:

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f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}

which converges by the ratio test if the following limit is less than 1:

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Like in the linked problem, the limit is 0 so the series for f(x) converges everywhere.

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