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Sholpan [36]
1 year ago
9

How long does it take $500 to double at a simple interest rate of 24%?

Mathematics
1 answer:
yuradex [85]1 year ago
3 0

Answer:

4 years and 2 months

Step-by-step explanation:

<u>Simple interest formula</u>

A = P(1 + rt)

where:

  • A = final amount
  • P = principal amount
  • r = interest rate (in decimal form)
  • t = time (in years)

Given:

  • A = $500 × 2 = $1,000
  • P = $500
  • r = 24% = 0.24

Substitute the given values into the formula and solve for t:

\implies \sf 1000 = 500(1 + 0.24t)

\implies \sf \dfrac{1000}{500}=(1 + 0.24t)

\implies \sf 2=1 + 0.24t

\implies \sf 1 = 0.24t

\implies \sf t=\dfrac{1}{0.24}

\implies \sf t=4 \frac{1}{6} \:years

\implies \sf t=4\:years\:2\:months

Therefore, it takes 4 years and 2 months for the initial investment of $500 to double at a simple interested rate of 24%.

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Step-by-step explanation:

We can think of this situation as a triangle rectangle (you can see it in the image below).

Here, we have a triangle rectangle with an angle θ, such that the adjacent cathetus to θ is 3 units long, and the cathetus opposite to θ is 4 units long.

Here we want to find cos(θ).

You should remember:

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We already know that the adjacent cathetus is equal to 3.

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