The perimeter of the figure = length of outer sides of the triangle and rectangle + perimeter of the semicircle ≈ 61.7 ft.
The perimeter of a figure is the length of its borders = sum of all its sides.
Perimeter of the semicircle = 1/2(2πr) = 1/2(2 × 3.14 × 5) = 15.7
Perimeter of the figure = length of outer sides of the triangle and rectangle + perimeter of the semicircle
Perimeter = 12 + 6 + 14 + 14 + 15.7
Perimeter = 61.7 ft.
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Answer:
5 less then a number divided by 4
Step-by-step explanation:
sqrt(73) = 8.54 feet.
Remark
My guess is without the legs.
The person bringing it in will not be able to get a table in that is longer than the hypotenuse of a right triangle.
Givens
a = 8
b = 3
c = ??
Formula
a^2 + b^2 = c^2
Solution
8^2 + 3^2= c^2
64 + 9 = c^2
c^2 = 73
c = sqrt(73)
c = 8.54
The table can be no longer than 8 feet 5 inches about.
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