Answer:
A is 0.2, B is 0.34, C is 63.02, and D is 91.16
Step-by-step explanation:
For A: 2 divided by 10, For B: 34 divided by 100, For C: 2 divided by 100 and added it to 63, and for D I did 16 divided by 100 and added it to 91.
Answer:
Step 3: 40 + 12 + (18 + 27) = 40 + 12 + 18 + 27
Step 4: 97 (its the answer)
Step-by-step explanation:
Step 3: 40 + 12 + (18 + 27) = 40 + 12 + 18 + 27 = 97
Step 4: 97
The question is incomplete. Here is the complete question:
Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.95 probability that he will hit it. One day, Samir decides to attempt to hit 10 such targets in a row.
Assuming that Samir is equally likely to hit each of the 10 targets, what is the probability that he will miss at least one of them?
Answer:
40.13%
Step-by-step explanation:
Let 'A' be the event of not missing a target in 10 attempts.
Therefore, the complement of event 'A' is 
Now, Samir is equally likely to hit each of the 10 targets. Therefore, probability of hitting each target each time is same and equal to 0.95.
Now, 
We know that the sum of probability of an event and its complement is 1.
So, 
Therefore, the probability of missing a target at least once in 10 attempts is 40.13%.
The <em><u>correct answer</u></em> is:
c)75.4 to 94.6
Explanation:
The formula for a confidence interval is:
,
where μ is the mean, z is the z-score associated with the level of confidence we want, σ is the standard deviation, and n is the sample size.
Our mean is 85, our standard deviation is 12, our sample size is 6, and since we want 95% confidence, our z-score is 1.96:
