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rjkz [21]
1 year ago
9

ΔXYZ has angles with the following measurements:

Mathematics
1 answer:
k0ka [10]1 year ago
3 0

Answer:

Below in bold.

Step-by-step explanation:

The 3 angles add up to 180 degrees as they are in a triangle.

So 10x - 33 + 4x - 19 + 100 - 2x = 180

12x = 180 + 33 + 19 - 100

12x = 132

x = 11.

So the 3 angles are

10(11) - 33 = 110 - 33 = 77 degrees

4(11) - 19  =  25 degrees

100 - 2(11) = 78 degrees

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The function f(x)= -6x+11 has a range given by {-37,-25,-13,-1}.Select the domain values of the function from the list 1,2,3,4,5
andreev551 [17]
The range is {-37,-25,-13,-1}. So you need to figure out what four numbers from this list of numbers (1,2,3,4,5,6,7,8), when applied to this
function, ( f(x)=-6x+11 ), equals these numbers that are in the range {-37,-25,-13,-1}.

So you apply each of these numbers (1,2,3,4,5,6,7,8) into the function (f(x)=-6x+11)
one by one.

f(1)=-6(1)+11=5
f(2)=-6(2)+11= -1
f(3)=-6(3)+11= -7
f(4)=-6(4)+11= -13
f(5)=-6(5)+11= -19
f(6)=-6(6)+11= -25
f(7)=-6(7)+11= -31
f(8)=-6(8)+11= -37
As you can see, f(2),f(4),f(6),and f(8) equal the numbers that are in the range {-37,-25,-13,-1}.
4 0
3 years ago
What is the product of (x + 5)(x + 5)?
77julia77 [94]

Answer:

x^2 + 25

Step-by-step explanation:

3 0
2 years ago
Rewrite with positive exponents a^-3 b^-5
amm1812

Answer:

1/a^3 and 1/b^5

6 0
3 years ago
Consider the differential equation:
Wewaii [24]

(a) Take the Laplace transform of both sides:

2y''(t)+ty'(t)-2y(t)=14

\implies 2(s^2Y(s)-sy(0)-y'(0))-(Y(s)+sY'(s))-2Y(s)=\dfrac{14}s

where the transform of ty'(t) comes from

L[ty'(t)]=-(L[y'(t)])'=-(sY(s)-y(0))'=-Y(s)-sY'(s)

This yields the linear ODE,

-sY'(s)+(2s^2-3)Y(s)=\dfrac{14}s

Divides both sides by -s:

Y'(s)+\dfrac{3-2s^2}sY(s)=-\dfrac{14}{s^2}

Find the integrating factor:

\displaystyle\int\frac{3-2s^2}s\,\mathrm ds=3\ln|s|-s^2+C

Multiply both sides of the ODE by e^{3\ln|s|-s^2}=s^3e^{-s^2}:

s^3e^{-s^2}Y'(s)+(3s^2-2s^4)e^{-s^2}Y(s)=-14se^{-s^2}

The left side condenses into the derivative of a product:

\left(s^3e^{-s^2}Y(s)\right)'=-14se^{-s^2}

Integrate both sides and solve for Y(s):

s^3e^{-s^2}Y(s)=7e^{-s^2}+C

Y(s)=\dfrac{7+Ce^{s^2}}{s^3}

(b) Taking the inverse transform of both sides gives

y(t)=\dfrac{7t^2}2+C\,L^{-1}\left[\dfrac{e^{s^2}}{s^3}\right]

I don't know whether the remaining inverse transform can be resolved, but using the principle of superposition, we know that \frac{7t^2}2 is one solution to the original ODE.

y(t)=\dfrac{7t^2}2\implies y'(t)=7t\implies y''(t)=7

Substitute these into the ODE to see everything checks out:

2\cdot7+t\cdot7t-2\cdot\dfrac{7t^2}2=14

5 0
3 years ago
PLEASEEEEE HELLPPPP ME I NEED HELP ASAPPP I CANNOT FAIL THIS!!!!!!!
Elodia [21]

Answer:

1. Both Dan and Tess are correct.

    Tess:

         0.15 * 24.50 = 3.675

         24.5 - 3.675 = 20.825

         0.1 * 20.825 = 2.0825

         20.825 + 2.0825 = 22.9075

    Dan:

         0.85 * 24.50 =  20.825

         20.825 * 1.1 = 22.9075

    Both Dan and Tess used methods that provided the correct answer. Both methods follow the same path, but Dan's method simply took less steps since he used percentages that would take out the correct number, unlike Tess' percentages which would give you the number that you would then need to take out.

2. First, convert Amy's and Mike's numbers to a decimal of the whole so it is easier to compare the numbers.

    13% = 0.13 of the whole

    Dan has 0.14 of the whole

    0.5/6 = 0.083.. of the whole

Dan used the greatest amount of milk, using 0.14 of the 6 gallon container.

3.

    2p + 12 = 58 | Create an equation to show the prices relations

    2p = 46 | Take out the price of the concert ticket to leave us with the passes.

    p = 23 | Divide by 2 to find the cost of each pass.

4.

    x ≤ (18 - 6.5 - 5.75)/1.15

    18 - 6.50 = 11.5 | Take out the price of the notebook from the total.

    11.5 - 5.75 = 5.75 | Take out the amount of money that she wishes to save.

    5.75 / 1.15 = 5 | Divide by the price of each candy to find the max amount that she can buy.

Andrea has enough money to buy up to 5 candy bars.

x ≤ 5

8 0
3 years ago
Read 2 more answers
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