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Snowcat [4.5K]
3 years ago
7

A bug is moving back and forth on a straight path. The velocity of the bug is given by vt=t2-3t. Find the average acceleration o

f the bug on the interval 1, 4.
Mathematics
1 answer:
g100num [7]3 years ago
3 0

Answer:

2 unit/time²

Step-by-step explanation:

Given the equation:

v(t) =t^2-3t

At interval ; 1, 4

V(1) = 1^2 - 3(1)

V(1) = 1 - 3

V(1) = - 2

At t = 4

V(4) = 4^2 - 3(4)

V(4) = 16 - 12

V(4) = 4

Average acceleration : (final - Initial Velocity) / change in time

Average acceleration = (4 - (-2)) ÷ (4 - 1)

Average acceleration = (4 + 2) / 3

Average acceleration = 6 /3

Average acceleration = 2

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Write the first five terms of the sequence in which the nth term is a_n=(n+1)!/n+1.
VikaD [51]

Answer:a) 1,2,6,24,120

Step-by-step explanation:

The formula for the nth term of the sequence is expressed as

n=(n+1)!/n+1

For the first term, n = 1. Therefore,

(1+1)!/(1+1) = 2!/2 = (2×1)/2 = 1

For the second tern, n = 2. Therefore,

(2+1)!/2+1 = 3! /3 = (3×2×1)/3 = 6/3 = 2

For the third term, n = 3, therefore

(3+1)!/3+1 = 4!/4 =(4×3×2×1)/4 = 6

For the fourth term, n = 4. Therefore

(4+1)!/4+1 = 5!/5 = (5×4×3×2×1)/5 = 24

For the fifth term, n = 5. Therefore

(5+1)!/5+1 = 6!/6 = 6× 5×4×3×2×1)/6 = 120

4 0
2 years ago
Read 2 more answers
What is the exact solution to the equation 4^5x=3^(x-2)<br> list the steps to get the answer
scoray [572]

Answer: x = -0.377

Step-by-step explanation:

We have the equation:

4^(5*x) = 3^(x - 2)

Now we can use the fact that:

Ln(A^x) = x*Ln(A)

Then we can apply Ln(.) to both sides of the equation to get:

Ln(4^(5*x)) = Ln(3^(x - 2))

(5*x)*Ln(4) = (x - 2)*Ln(3)

(5*x)*Ln(4) - x*Ln(3) = -2*Ln(3)

x*(5*Ln(4) - Ln(3)) = -2*Ln(3)

x = -2*Ln(3)/(5*Ln(4) - Ln(3)) = -0.377

6 0
3 years ago
Answer quick find the coordinates
Mekhanik [1.2K]

Answer:

  (-4, -3), (4, -1), (8, 0), (12, 1)

Step-by-step explanation:

The x- and corresponding y-values are listed in the table. Put each pair in parentheses, <em>x-value first</em>. (That is an <em>ordered pair</em>.)

  (x, y) = (-4, -3) . . . . from the first table entry

  (x, y) = (4, -1) . . . . from the second table entry

  (x, y) = (8, 0) . . . . from the third table entry

  (x, y) = (12, 1) . . . . from the last table entry

3 0
3 years ago
2x3 + x2 + 7x - 6)-(- 2x + 10x + 10x+9)​
AVprozaik [17]

Answer:

2x³ + x² - 11x - 15

Step-by-step explanation:

Step 1: Write out expression

2x³ + x² + 7x - 6 - (-2x + 10x + 10x + 9)

Step 2: Distribute negative

2x³ + x² + 7x - 6 + 2x - 10x - 10x - 9

Step 3: Combine like terms (x)

2x³ + x² + 9x - 10x - 10x - 9 - 6

2x³ + x² - x - 10x - 9 - 6

2x³ + x² - 11x - 9 - 6

Step 4: Combine like terms (constants)

2x³ + x² - 11x - 15

5 0
3 years ago
X^{2} +(3a+4b)x+(2a^{2} +5ab+3b^{2} )
kupik [55]

Answer:

∣x+a+b∣∣x+2a+3b∣

Step-by-step explanation:

∣x+a+b∣∣x+2a+3b∣

4 0
2 years ago
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