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Leona [35]
3 years ago
10

Scenario: A new Swimming pool is opening up this summer in the Bronx. Students that are 13 - 18 years old can use the pool, gym

, and exercise room with a membership. To get a membership , you must pay $40 to sign-up and $15 every two months. Create a table to determine how much u will pay in 1 yr...help me plz

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
3 0
The answer to your question is 15(12)+40=?
15 being the per month fee, 12 being all 12 months, and 40 being the sign up fee. You can also put 15x12+40=?
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RUDIKE [14]

Answer:

46$

Step-by-step explanation:

20+20=40, 5% of 40=2, 42, +4, 46. (the 4 comes from the 10%)

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3 years ago
What is the value of log256 4
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Step-by-step explanation: We will solve log256 4 in several steps to solve for x.

Step 1: Log256 4 = x

Step 2: 256x = 4                    ( Next, Use exponents )

Step 3: (2^8)x = 2^2

Step 4: 2^8x = 2^2

Step 5: 8x = 2  (Solve for x0

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Step 7 (The Answer) x, or log256 4 = 1/4 or 0.25

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The probability that a randomly selected student from the class has brown eyes , given they are male

P(\frac{B}{M} ) = 0.3030

Step-by-step explanation:

<u>Explanation</u>:-

Given data

                      Brown           Blue           Hazel           Green

Females           13                  4                  6                   9          

Males                10                  2                 9                   12

<em>Let 'B' be the event of brown eyes </em>

<em>Total number of males n(M) = 33</em>

Let B/M be the event of randomly selected student from the class has brown eyes given they are male

<em>The probability that a randomly selected student from the class has brown eyes , given they are male</em>

<em></em>P(\frac{B}{M} ) = \frac{n(B)}{n(M)}<em></em>

<em>From table the brown eyes from males = 10</em>

P(\frac{B}{M} ) = \frac{10}{33}

P(\frac{B}{M} ) = 0.3030

<u>Final answer</u>:-

The probability that a randomly selected student from the class has brown eyes , given they are male

P(\frac{B}{M} ) = 0.3030

8 0
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