Based on the information given, the computation shows that the distance between them is 2.47 miles.
<h3>
Solving the distance.</h3>
Since one has bearing 41°45', this will be: = 41° + (45/60) = 41° + 0.75 = 41.75°.
The other has bearing 59°13'. This will be:
= 59° + (13/60) = 59° + 0.22 = 59.22°.
The difference of the angles will be:
= 59.22° - 41.75°
= 17.47°
Let the distance between them be represented by c. Therefore, we'll use cosine law to solve the question. This will be:
c² = a² + b² - 2ab cos 17.47°
c² = 20² + 20² - (2 × 20 × 20 × 0.19)
c² = 6.07459
c = 2.47
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4×3=12
12+12=24, 3+3=6
24+6=30
So 12 × 3 = 36 square ft.
You find values of 28 that add to -11! in this case thats -7 and -4. after that just plug in (x-7)(x-4)=0 so: x=4, x=7
<span>we have that
the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]
we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]
z1=3[cos 110° + i sin 110°]
cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]
z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is
</span>z1=3[cos 110° + i sin 110°]<span>
</span>z2=3[cos 230° + i sin 230°]
z3=3[cos 350° + i sin 350°]<span>
</span>
Answer:
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Step-by-step explanation:
