Mohjjbn bn hjbjn hjbnm

1 answer:

7 0

Yup yup, I understand your question: jejsusuehsbhs lakksjjwhe eiksjsjnesh is the answer you’re looking for. I’m happy to help

You might be interested in

75% of the normal price of headphones is 45$. What's the normal price?

Brums [2.3K]

Answer:

60$ is the normal price.

Why:

Because if 45$ is 75%, then 30$ is 50%, 15 is 25%, and 0 is 0%. 50% + 50% = 100%. (That's how I did this one, anyway. This works on any 25%, 50%, or 75% problem.)

4 0

2 years ago

(3x-5)/(x-5)>=0 <br> How do I get the answers for this problem?

Diano4ka-milaya [45]

$\frac{3x-5}{x-5}$ > 0

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: $\frac{3x-5}{x-5}$ = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = $\frac{5}{3}$
Sixth, from the values of x above, we have these 3 intervals to test:
x < $\frac{5}{3}$
$\frac{5}{3}$ < x < 5
x > 5
Seventh, pick a test point for each interval.

1. For the interval x < $\frac{5}{3}$ :
Let's pick x - 0. Then, $\frac{3x0-5}{0-5}$ > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval $\frac{5}{3}$ < x < 5:
Let's pick x = 2. Then, $\frac{3x2-5}{2-5}$ > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, $\frac{3x6-5}{6-5}$ > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < $\frac{5}{3}$ and x > 5

Answer: x < $\frac{5}{3}$ and x > 5

3 0

3 years ago

Hey if you're willing to help me with this, it will be very much appreciated, thanks maties and mates.

Nastasia [14]

Answer:

Width=37in

Length=55in

Step-by-step explanation:

Let x in be the width dimension, the length dimension will be x+18 in. Area of a rectangle is calculated as A=lw. Given the area as2143 sq in, x can be calculated as:

$Area= x(18+x)\\\\=18x+x^2\\\\$