What is the lcm of 12 and 18
2 answers:
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I'll do a and e on the first one to show you how to do it
Then See if you can do the rest
a. 6(-3)<span><span>
</span></span>
When your multiplying or dividing with negative numbers; If one of your numbers is negative like the one above, your answer will be negative
So 6 × 3 = 18 ; but since there is a negative on the 3 your answer will be -18
e. -20 ÷ 5
same for this; 20 ÷ 5 = 4, but since the 20 is negative the answer will be <span>-4
You do b, c, d, and f on the first question. Tell me what you get and we'll go from there
</span>Now for the second question <span>
</span>I will do a and d to show you how to do this then you do the rest<span> (I'm inserting a picture with these)
</span>a.
First go ahead and turn the fractions into improper fractions, this makes them a bit easier to work with. When multiplying fractions; they do not need a common denominator, all you do is multiply top by top and bottom by bottom.<span>
However, when you add and subtract fractions you MUST have a common denominator
</span>d. (-4.25)(2) + (-4.25)(-2)
remember from the first problem a negative times a positive gives you a negative<span>
but when you times a negative by a negative you get a positive
Now you try b and c; let me know what you get, and we'll go from there!
</span>
Then See if you can do the rest
a. 6(-3)<span><span>
</span></span>
When your multiplying or dividing with negative numbers; If one of your numbers is negative like the one above, your answer will be negative
So 6 × 3 = 18 ; but since there is a negative on the 3 your answer will be -18
e. -20 ÷ 5
same for this; 20 ÷ 5 = 4, but since the 20 is negative the answer will be <span>-4
You do b, c, d, and f on the first question. Tell me what you get and we'll go from there
</span>Now for the second question <span>
</span>I will do a and d to show you how to do this then you do the rest<span> (I'm inserting a picture with these)
</span>a.
First go ahead and turn the fractions into improper fractions, this makes them a bit easier to work with. When multiplying fractions; they do not need a common denominator, all you do is multiply top by top and bottom by bottom.<span>
However, when you add and subtract fractions you MUST have a common denominator
</span>d. (-4.25)(2) + (-4.25)(-2)
remember from the first problem a negative times a positive gives you a negative<span>
but when you times a negative by a negative you get a positive
Now you try b and c; let me know what you get, and we'll go from there!
</span>
Its algebra. The original equation is 
To solve for a variable, we reverse the order of operations, beginning with addition/subtraction, and then multiplication/division. To remove a number from one side, we must do the opposite to the other side. In this case, to get rid of the -121 we must add 121 to the -164. This gives us -43. Then, to get the x by itself, we must multiply the other side by 3. -43*3=129
When we are doing the opposite of an operation to the other side, we are really reversing the operation and, to keep both sides equal, we must do whatever we have done to one side to the other side. So when we have -121, we add 121 as it equals 0, therefore it is gone. Since a equation must be balanced, we have to do what we did to the other side (adding 121).
To solve for a variable, we reverse the order of operations, beginning with addition/subtraction, and then multiplication/division. To remove a number from one side, we must do the opposite to the other side. In this case, to get rid of the -121 we must add 121 to the -164. This gives us -43. Then, to get the x by itself, we must multiply the other side by 3. -43*3=129
When we are doing the opposite of an operation to the other side, we are really reversing the operation and, to keep both sides equal, we must do whatever we have done to one side to the other side. So when we have -121, we add 121 as it equals 0, therefore it is gone. Since a equation must be balanced, we have to do what we did to the other side (adding 121).