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2 years ago

Three increased by one equals the quotient of eight and two in equation form

Mathematics

2 answers:

Ostrovityanka [42]2 years ago

6 0

Answer:

yes

Step-by-step explanation:

it is yes because yes means Y E S, therefore translating to YES

ivanzaharov [21]2 years ago

5 0

Answer:

yes

Step-by-step explanation:

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garik1379 [7]

The complete question is

"Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real number solutions? (The related quadratic function will have two x-intercepts.) Check all that apply.

0 = 2x^2 – 7x – 9

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The quadratic equations that have real number solutions are; 4x^2 – 3x – 1, and 2x^2 – 7x – 9.

<h3>What is the formula for Discriminant?</h3>

The formula for finding the discriminant is

$b^2 - 4ac$

The solution contains the term $\sqrt{b^2 - 4ac}$ which will be:

Real and distinct if the discriminant is positive

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Non-real and distinct roots if the discriminant is negative

For the quadratic equation $2x^2 - 7x - 9$

$b^2 - 4ac$

$= (-7) ^2 - 4( 2) ( -9)\\\\= 49 + 72 = 121$

This equation has two real number solutions.

For the quadratic equation $4x^ 2 - 3x- 1$

$b^2 - 4ac$

$= (-3) ^2 - 4( 4) ( -1)\\\\= 9 + 16 = 25$

This equation will have two real number solutions.

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