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mariarad [96]
1 year ago
12

Help ??? I need help lol! Please

Mathematics
2 answers:
AveGali [126]1 year ago
7 0

Answer:

Step-by-step explanation:

Answer: Choose option 2.

artcher [175]1 year ago
3 0

Answer: Choose option 2.

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Graph the linear equation. Find three
Sever21 [200]
Y=1/3x+2
(-6,0)
(0,2)
(6,4)
6 0
3 years ago
Find the missing angle.
Vika [28.1K]

Answer:

X = 45

Step-by-step explanation:

Hope it will be helpful for you.

8 0
2 years ago
If x – 10 is a factor of x2 – 8x – 20, what is the other factor?
kkurt [141]

Answer:

Step-by-step explanation:

x²-8x-20

=x²-10x+2x-20

=x(x-10)+2(x-10)

=(x-10)(x+2)

second factor is x+2

5 0
3 years ago
Read 2 more answers
How do u do this.I need major help on it
Tpy6a [65]
Look for what 'y' is when t = 1 and t = 2. Go to the graph, look at 1 on the bottom axis and go up till you find the point, then go all the way to the left to see what the y-value is, in this case it should be 1200. If you do the same with t = 2, you will get 2400. So our two ordered pairs are:

(1, 1200), (2, 2400)

We can find the slope of these two points by plugging them into the slope formula:

\sf m=\dfrac{y_2-y_1}{x_2-x_1}

For points in the form of (x1, y1), (x2, y2). Plug in what we know:

\sf m=\dfrac{2400-1200}{2-1}

Subtract:

\sf m=\dfrac{1200}{1}

Divide:

\sf m=1200

This is the slope, so we can write the equation:

\boxed{\sf y=1200t}
4 0
3 years ago
Which of the following is not a factor of x^3 – 3x^2 – 4x + 12?
Slav-nsk [51]

Answer:

c. (x + 3)

Step-by-step explanation:

using factor theorem

if x - 3 is a factor then p(a) = 0

p(a)= x^3 - 3x^2 - 4x + 12

a.(x-3)

p(3) = (3)^3 - 3(3)^2 - 4(3) + 12

= 27 - 27 - 12 + 12

= 0

therefore x-3 is a factor

b.(x + 2)

p(-2) = (-2)^3 - 3(-2)^2 - 4(-2) + 12

= -8 -12 + 8 + 12

,= 0

therefore x + 2 is a factor

c.(x + 3)

p(-3) = (-3)^3 - 3(-3)^2 - 4(-3) + 12

= -27 -27 + 12 + 12

= -30

therefore x + 3 is not a factor

d.(x-2)

p(2) = (2)^3 - 3(2)^2 - 4(2) + 12

= 8 -12 - 8 + 12

= 0

therefore x - 2 is a factor

4 0
3 years ago
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