Answer:
<h2>(g-f)(10) = - 71</h2>
Step-by-step explanation:
f(x) = x² - 1
g(x) = 2x + 8
To find (g-f)(10) first find ( g - f)(x)
To find ( g - f)(x) subtract f(x) from g(x)
That's
( g - f)(x) = 2x + 8 - ( x² - 1)
Remove the bracket
( g - f)(x) = 2x + 8 - x² + 1
Simplify
( g - f)(x) = - x² + 2x + 9
To find (g-f)(10) substitute the value in the bracket that's 10 into ( g - f)(x)
That is
(g-f)(10) = -(10)² + 2(10) + 9
= - 100 + 20 + 9
= - 100 + 29
= - 71
Hope this helps you
The decimal number for seventy eight hundred-thousandths is 5.
<h3>
What is decimal number?</h3>
A decimal is a number that consists of a whole and a fractional part
The decimal numeral system is the standard system for denoting integer and non-integer numbers.
What is the decimal number for seventy eight hundred-thousandths?
= 78 x 10⁻⁵
<u>note</u>: a hundred thousandth = 10⁻⁵
= 0.00078
Thus, the decimal number for seventy eight hundred-thousandths is 5.
Learn more about decimal number here: brainly.com/question/1827193
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Y = 3 because in a rectangle, the diagonals are ALWAYS congruent. so you would have:
5y - 2 = 4y + 1
-4y+2 -4y + 2
y = 3
Answer:
$12
Step-by-step explanation:
Assuming you meant $6 per 1/2 hour
since by multiplying 1/2 by 2 we get 1 ( our unit rate) 6*2 = 12
whole number
12
fraction
12/1
Brainliest would be appreciated if this is helpful. Let me know if you have more questions
Hope this helps!
Answer: x^2 + y^2 -10y = 0
Step-by-step explanation:
Cartesian coordinates, also called the Rectangular coordinates, isdefined in terms of x and y. So, for the problem θ has to be eliminated or converted using basic foundations that are described by the unit circle and the right triangle trigonometry.
r= 10sin(θ)
Remember that:
x= r × cos(θ)
y= r × sin(θ)
r^2= x^2 + y^2
Multiply both sides of the equation by r. This will give:
r × r = 10r × sin(θ)
r^2 = 10r × sin(θ)
x^2 + y^2= 10r × sin(θ)
Because y= r × sin(θ), we can make a substitution. This will be:
x^2 + y^2= 10y
x^2 + y^2 -10y = 0
The above equation is the Rectangular coordinate equivalent to the given equation.
