Answer:
75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.
Step-by-step explanation:
The question is missing. It is as follows:
Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64
Assume that the population of x values has an approximately normal distribution.
Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)
75% Confidence Interval can be calculated using M±ME where
- M is the sample mean weight of the wild mountain lions (
)
- ME is the margin of error of the mean
And margin of error (ME) of the mean can be calculated using the formula
ME=
where
- t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)
- s is the standard deviation of the sample(31.4)
Thus, ME=
≈16.66
Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5
Answer:
1.) supplementary m<1+m<2=180 and m<2+m<3=180
2.) congruent, supplementary
Step-by-step explanation:
the answers are in this order above
Answer:
29.3 hours overtime
Step-by-step explanation:
450-300= 150
150/5.12= 29.3
Answer:
what......................
Answer and Step-by-step explanation:
When making a perpendicular line, you take 2 points on a straight line.
- You put the compass on the two points, making marks above and below to be able to draw the line.
When making an angle bisector line, you use the angle and 2 points to make a straight line that will bisect the angle.
- You put the compass on the angle, making an arc from the two lines that join to make the angle. Then, you put your compass on where the arc meets the lines, and make a mark, which you then draw a line through.
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