Question

Which zero pair could be added to the function fon) = x2 + 12x + 6 so that the function can be written in vertex form?

Answer 1

ANSWER

36,-36

EXPLANATION

The given function is:

$f(x) = {x}^{2} + 12x + 6$

To write this function in vertex form;

We need to add and subtract the square of half the coefficient of x.

The coefficient of x is 12.

Half of it is 6.

The square of 6 is 36.

Therefore we add and subtract 36.

Hence the zero pair is:

36, -36.

The correct answer is D.

Answer 2

Answer:

Last option: 36,-36​

Step-by-step explanation:

The vertex form of the function of a parabola is:

$y=a(x-h)^2+k$

Where (h,k) is the vertex.

To write the given function in vertex form, we need to Complete the square.

Given the Standard form:

$y=ax^2+bx+c$

We need to add and subtract $(\frac{b}{2})^2$ on one side in order to complete the square.

Then, given $y=x^2+12x+6$, we know that:

$(\frac{12}{2})^2=6^2=36$

Then, completing the square, we get:

 $y=x^2+12x+(36)+6-(36)$

$y=(x+6)^2-30$ (Vertex form)

Therefore, the answer is: 36,-36​