Alex runs 3 laps around a course that is 1 3/4 miles long how far did he run?

100 POINTS!!! PLEASE I NEED HELP DUE TODAY!!!!

Volgvan

Using weighed averages, it is found that:

The final grade is 91.
The final grade is 66.8.
The higher grade would be 79.55, with the second grading scheme.
On average, she sold $48,280 per day.
On average, she makes $12.5 per hour.

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To find the weighed average, we multiply each value by it's weight.

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Question 1:

Grade of 91, with a weight of 67%.
Grade of 91, with a weight of 33%.

Thus:

$F = 91\times0.67 + 91\times0.33 = 91$

The final grade is 91.

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Question 2:

Grade of 83, with a weight of 40%(highest grade).
Grade of 60, with a weight of 30%.
Grade of 52, with a weight of 30%.

Thus:

$F = 83\times0.4 + 60\times0.3 + 52\times0.3 = 66.8$

The final grade is 66.8.

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Question 3:

With teacher 1:

75 with a weight of 25%.
80 with a weight of 10%.
85 with a weight of 40%.
62 with a grade of 25%.

Thus:

$F_1 = 75\times0.25 + 80\times0.1 + 85\times0.4 + 62\times0.25 = 76.25$

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With teacher 2:

75 with a weight of 15%.
80 with a weight of 10%.
85 with a weight of 60%.
62 with a weight of 15%.

Thus:

$F_2 = 75\times0.15 + 80\times0.1 + 85\times0.6 + 62\times0.15 = 79.55$

The higher grade would be 79.55, with the second grading scheme.

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Question 4:

Average of $36,432, with a weight of $\frac{3}{3+10} = \frac{3}{13}$
Average of $51,834, with a weight of $\frac{10}{13}$

Thus:

$A = 36432\frac{3}{13} + 51834\frac{10}{13} = \frac{36432\times3 + 51834\times10}{13} = 48280$

On average, she sold $48,280 per day.

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Question 5:

Average of $14.84, with a weight of $\frac{6}{6+8} = \frac{6}{14} = \frac{3}{7}$
Average of $10.76, with a weight of $\frac{4}{7}$

Thus:

$A = 14.84\frac{3}{7} + 10.76\frac{4}{7} = \frac{14.84\times3 + 10.76\times4}{7} = 12.5$

On average, she makes $12.5 per hour.

A similar problem is given at brainly.com/question/24398353

5 0

3 years ago

Complete each statement in the steps to solve x2 – 6x – 7 = 0 using the process of completing the square. Isolate the constant b

Tomtit [17]

"Isolate the constant by adding 7 to both sides of the equation."
This step separates the non-squareable 7 and the squareable $x^2 - 6x$ .

"Add 9 to both sides of $x^2 - 6x = 7$ to form a perfect square trinomial while keeping the equation balanced."
After separating the non-squareable, add the number which makes the first or left side a perfect square trinomial. The formula to find the number is: $c = {\frac{b}{2} }^{2}$ .
When we plug the values: $c = { \frac{ - 6}{2} }^{2}$
Simplify: $c = {( - 3)}^{2} = 9$

"Write the trinomial $x^2 - 6x + 9$ as $(x - 3)$ squared."
When you factor $x^2 - 6x + 9$ , you will get $(x - 3) \times (x - 3)$ .

"Use the square root property of equality to get $x - 3 = ± \sqrt{16}$ ."
The 16 is coming from the part when we add 9. We needed 9 on the left side for a perfect square, but to protect the balance of the equality, we need to add 9 to the right side too. When we add 7 and 9, we got 16, and that is where it came from.

"Isolate the variable x to get solutions of -1 and 7."
To isolate x we branched the plus-minus sign:
$x - 3 = 4 \: \: \: x = 4 + 3 = 7 \\ \\ x - 3 = - 4 \: \: \: x = - 4 + 3 = - 1$

8 0

3 years ago

Read 2 more answers

Whats the inverse of 17=1+9n

WINSTONCH [101]

Answer:

$\frac{9}{16}$