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diamong [38]
2 years ago
10

1. Select all the true statements.

Mathematics
1 answer:
Andreyy892 years ago
6 0

Answer:

A , B , D

Step-by-step explanation:

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What is 8 x 23<br> + 6<br> 3 + 2
kicyunya [14]

Answer:

8x23 +6+3+2 = 195

Step-by-step explanation:

used PEMDAS <3 hope this helps

5 0
3 years ago
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the length of a rectangle is 6 units shorter than 1/4 of the width x. Write an expression for the perimeter of the rectangle.
USPshnik [31]
L=x/4 -6

Perimeter= Length x Width
Width=x
Length= x/4 -6

P=LxW
P=(x/4-6)x(x)
5 0
3 years ago
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Need help with this question asap pleasee
tresset_1 [31]

Answer:

The second choice is correct

Step-by-step explanation:

Here, we want to get the correct statement

As can be seen, while 2 is the angle at the circumference, 1 is the angle at the center

Mathematically, we know that angle at the center is two times the angle at the circumference

Thus,

m1 = 1/2 (m2)

or m2 = 2 * m1

7 0
3 years ago
There are 15 hats on a rack and 9 of them are orange<br>What percentage of the hats are NOT orange?​
dmitriy555 [2]

Answer:

40%

Step-by-step explanation:

15-9=6

6/15=2/5=40/100=40%

4 0
3 years ago
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2. Lab groups of three are to be randomly formed (without replacement) from a class that contains five engineers and four non-en
Anna11 [10]

Answer:

The number of different lab groups possible is 84.

Step-by-step explanation:

<u>Given</u>:

A class consists of 5 engineers and 4 non-engineers.

A lab groups of 3 are to be formed of these 9 students.

The problem can be solved using combinations.

Combinations is the number of ways to select <em>k</em> items from a group of <em>n</em> items without replacement. The order of the arrangement does not matter in combinations.

The combination of <em>k</em> items from <em>n</em> items is: {n\choose k}=\frac{n!}{k!(n-k)!}

Compute the number of different lab groups possible as follows:

The number of ways of selecting 3 students from 9 is = {n\choose k}={9\choose 3}

                                                                                         =\frac{9!}{3!(9 - 3)!}\\=\frac{9!}{3!\times 6!}\\=\frac{362880}{6\times720}\\ =84

Thus, the number of different lab groups possible is 84.

8 0
3 years ago
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