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Stells [14]
2 years ago
8

A school event requires at least 3 parents for every 10 kids. How many parents for 50 kids?

Mathematics
1 answer:
padilas [110]2 years ago
3 0

For 50 kids, the number of parents that would be required would be 15 parents.

<h3>How many parents for 50 kids? </h3>

The first step is to determine the number of parents needed for 1 kid:

1 kid required 3/10 parents

Now, multiply that ratio by 50: 3/10 x 50 = 15 parents

To learn more about multiplication, please check: brainly.com/question/17192010

#SPJ1

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Choose the triangle that seems to be congruent to △AEC.<br><br><br><br> △BFC<br> △ABD<br> △EFD
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Given the following exponential function, identify whether the change represents growth or decay, and determine the percentage r
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7 0
3 years ago
Read 2 more answers
If ef bisects angle ceb,angle cef=7x+31 and angle feb=10x-3
Nastasia [14]

Given : Angle  < CEB is bisected by EF.

< CEF = 7x +31.

< FEB = 10x-3.

We need to find the values of x and measure of < FEB, < CEF  and < CEB.

Solution: Angle  < CEB is bisected into two angles < FEB and < CEF.

Therefore,   < FEB = < CEF.

Substituting the values of < FEB and < CEF, we get

10x -3 = 7x +31

Adding 3 on both sides, we get

10x -3+3 = 7x +31+3.

10x = 7x + 34

Subtracting 7x from both sides, we get

10x-7x = 7x-7x +34.

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Dividing both sides by 3, we get

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Plugging value of x=11.33 in < CEF = 7x +31.

We get

< CEF = 7(11.33) +31 =  79.33+31 = 110.33.

< FEB  = < CEF =  110.33 approximately

< CEB = < FEB +  < CEF  = 110.33 +110.33 = 220.66 approximately



7 0
3 years ago
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