A school event requires at least 3 parents for every 10 kids. How many parents for 50 kids?

Mathematics

1 answer:

padilas [110]1 year ago

3 0

For 50 kids, the number of parents that would be required would be 15 parents.

<h3>How many parents for 50 kids? </h3>

The first step is to determine the number of parents needed for 1 kid:

1 kid required 3/10 parents

Now, multiply that ratio by 50: 3/10 x 50 = 15 parents

To learn more about multiplication, please check: brainly.com/question/17192010

#SPJ1

You might be interested in

A store buys an item for $94. The store then prices the item to sell to customers. What is the selling price (in dollars) the st

AnnyKZ [126]

Answer:

$152.28

Step-by-step explanation:

In order to determine the markup, multiply the original price by 62%

94 x 62% = 94 x .62 = 58.28

In order to determine the sale price, add the markup to the original price.

94 + 58.28 = $152.28

3 0

3 years ago

There are 200 paperweights in a box. The mass of each paperweight is 0.085 kilogram. The mass of the empty box is 560 grams. Wha

serious [3.7K]

17560grams.

each paperweight is 85 grams. (a kilogram is 1000 grams)

85*200= 17,000
17,000+560=17,560

7 0

3 years ago

Need help with math will star plz help and explain

fiasKO [112]

3x-25=2x-10 add 25 on both sides
3x=2x+15 then subtract 2x on both sides
<span>X=15 </span>
Plug in x to "3x-25" which would equal 20
<span>M< L = 20 so, 180-20= 160 </span>
<span>M=160

</span>

4 0

3 years ago

Find how many solutions there are to the given equation that satisfy the given condition.

den301095 [7]

Answer:

17550 solutions

Step-by-step explanation:

Given that:

y1 +y2+y3+y4=27

where;

(yi ≥ 0 and yi $\epsilon$ $\mathbb {Z}$ )

The no. of a nonnegative integer determines the number of ways to choose 27 objects from (4) distinct objects with repetition regardless of the order.

i.e

$\bigg(^{27}_{4} \bigg)$