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3 years ago

8

Plz help it was due last week :((((

1 answer:

vesna_86 [32]3 years ago

4 0

Formula= (y2-y1)/ (x2-x1)

(-5 - -1) / (-2 - -4)
(-4) / (2) = -2
q8 is C

(-3 - -3) / (8 - 4)
(0) / (4) = 0
q12 is D

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A certain gas station requires a minimum of $5 to use a debit card. You plan on buying a soda and however many bags of cheetos r

vekshin1

Answer:

1.20 + 1.40x ≥ 5, or $1.20 + $1.40x ≥ $5

Step-by-step explanation:

So since you are only buying 1 soda and you are buying multiple bags of Cheetos so you are able to use you debit card and meet the requirement of at least $5, you can make the inequality:

1.20 + 1.40x ≥ 5, or $1.20 + $1.40x ≥ $5

where x is the number of bags of Cheetos.

6 0

3 years ago

No links please

pogonyaev

It’s D (,10) and R=2 is this algebra ?

7 0

3 years ago

What is 1 2/3 to the 3rd power

hammer [34]

Answer:

$2\frac{7}{9}$

Step-by-step explanation:

In order to get the answer to this question you must change the mixed number into a improper fraction then multiply the improper fraction as many times as it's exponent.

$1\frac{2}{3} ^3$

Turn the mixed number into a improper fraction:

$1\frac{2}{3} =\frac{5}{3}$

$=\frac{5}{3}^3$

$\frac{5}{3} ^3=\frac{5}{3} \times\frac{5}{3} \times\frac{5}{3}$

Now multiply:

$\frac{5}{3} \times\frac{5}{3} =\frac{25}{9}$

$\frac{25}{9} \times\frac{5}{3} =\frac{75}{27}$

Turn the improper fraction into a mixed number:

$\frac{75}{27} =2\frac{7}{9}$

$=2\frac{7}{9}$

Hope this helps.

5 0

4 years ago

Hello, help me please)

AlladinOne [14]

Answer:

Given equation:

$10^{5x-2}=2^{8x-3}$

Take natural logs of both sides:

$\implies \ln 10^{5x-2}= \ln 2^{8x-3}$

$\textsf{Apply log Power law}: \quad \ln_ax^n=n\ln_ax$

$\implies (5x-2)\ln 10=(8x-3) \ln 2$

Expand brackets:

$\implies 5x\ln 10 - 2\ln 10=8x \ln 2 -3 \ln 2$

Collect like terms:

$\implies 5x\ln 10 - 8x \ln 2 =2\ln 10-3 \ln 2$

Factor left sides:

$\implies x(5\ln 10 - 8 \ln 2) =2\ln 10-3 \ln 2$

$\textsf{Apply log Power law}: \quad \ln_ax^n=n\ln_ax$

$\implies x(\ln 10^5 - \ln 2^8) =\ln 10^2- \ln 2^3$

$\textsf{Apply log Quotient law}: \quad \ln_a\frac{x}{y}=\ln_ax - \ln_ay$

$\implies x\left(\ln\left(\dfrac{10^5}{2^8}\right)\right) =\ln\left(\dfrac{10^2}{2^3}\right)$

Simplify:

$\implies x\left(\ln\left(\dfrac{3125}{8}\right)\right) =\ln\left(\dfrac{25}{2}\right)$

$\implies x=\dfrac{\ln\left(\dfrac{25}{2}\right)}{\ln\left(\dfrac{3125}{8}\right)}$

$\implies x=0.4232297737...$

6 0

2 years ago

Jaxon’s start-up business makes a profit of $450 during the first month. However, the company records a profit of -$60 per month

omeli [17]

1st month +450

-60 x 4 months = -240

6th month + 125

Total: 450 - 240 + 125 = $335 profit

7 0

3 years ago