We have that
smaller figure
ha=8.7
ra=1.6
larger figure
hb=10.44
rb=1.92
ha/hb=8.7/10.44----> 0.83
ra/rb=1.6/1.92-------> 0.83
ratio smaller figure to the larger figure
1.6/1.92-------> divided by 1.6 both members[1.6/1.6]/[1.92/1.6]-------> 1/1.2
the ratio ha/hb is equal to the ratio ra/rb
so
the smaller figure and the larger figure are similar
and
the ratio smaller figure to the larger figure is equal to----> 1/1.2
the answer is
the option yes 1/1.2
Y = -7x + 2
y = 9x - 14
-7x + 2 = 9x - 14
14 + 2 = 9x + 7x
16 = 16x
1 = x
y = -7x + 2
y = -7(1) + 2
y = -7 + 2
y = -5
solution is : (1,-5) <==
assuming you means k = log_2(3) [as log(2)3 is the same thing as 3log(2) due to multiplication being commutative]
given log(ab) = log(a) + log(b)
log_2(48) = log_2(3) + log_2(16)
Example
2^3 4^2
2×2×2=6 4×4=16
All you do is multiply the number by the exponent however many times the exponents is
