The sum of 7-1 and 7-2 will be a rational number because sum of rational numbers is a rational numbers.
A rational number is a number which can be written in p/q form where q≠0.
We know that when two rational numbers is added then the sum is also a rational number. And when two rational numbers are subtracted then the difference is also a rational number.
So in the given question, lets study the term differently that is,
i) 7 - 1 is a rational number because their difference is equal to 6 and it can be written in p/q form which is 6/1.
ii) 7 – 2 is also a rational number as their difference will be 5 which is a rational and can be written in p/q form which is 5/1.
So when these two rational numbers are added their sum will also be a rational number which is 11.
Learn more about rational numbers here : brainly.com/question/12088221
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There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Since we are dealing with a radical then x - 5 ≥ 0, for real values
x = 4 is less than 5 , hence is not in the domain
In i hour it would be
60/3=20
20x24=480
480x24=11520.
11520 is your answer! :)
Hope this helps!!
~Summer
