All categories

2 years ago

What is the inequality shown? -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9

Mathematics

1 answer:

vitfil [10]2 years ago

5 0

Step-by-step explanation:

well it could be -10 < x < 10

or -9 ≤ x < 10

or -10 < x ≤ 9

or -9 ≤ x ≤ 9

You might be interested in

Graph the line that has slope 1/2 and y intercept (0,-1).

puteri [66]

Answer: I added an attachment of what the graph should look like! :)

Step-by-step explanation:

5 0

1 year ago

Use the substitution method to solve the system of equations 5x-2y=9 3x+4y=-5

krek1111 [17]

Answer:

(1,-2)

Step-by-step explanation:

x= 1

y= 2

3 0

1 year ago

Calculate the axis of symmetry in the equation Y = (x+1) (x-4)

algol [13]

Answer:

Every parabola has a turning point called the axis of symmetry,so for this question you just have to find the turning points

x turning point= -b/2a,and the y turning point is gotten by replacing the value of x in the equation

y=(x+1)(x-4)

=x^2-3x-4

a is 1,b is -3 and c is -4

x= -(-3)/2(1)

=1.5

and y=x^2-3x-4

=1.5^2-3(1.5)-4

= -6.25

therefore the axis of symmetry is (1.5,-6.25)

I hope this helps

6 0

2 years ago

Edgar has taken out a $6,250 unsubsidized Stafford loan to fund his four-year undergraduate degree. The loan has a duration of 1

abruzzese [7]

The present worth of the loan is $6,250
The start of payment will after 4 years
The nominal interest rate is 6.1% compounded monthly which is equal to 6.27% effective.

The future worth (after graduation) of the loan is
F = $6,250 (1 + 0.0627)^4 = $7,971.18

The interest is
$7,971.18 - $6,250 = $1,721.18
I didn't round off when solving these so it's not the exact answer among the choices but the closest is letter B $1,722.22

5 0

2 years ago

To three decimal places, find the average value of f(x) = 2x2 + 3 on the interval [0, 2].

salantis [7]

The formula for the average value of a function is $\frac{1}{b-a} \int\limits^b_a {f(x)} \, dx$ where b is the upper bound and a is the lower. For us, this formula will be filled in accordingly. $\frac{1}{2} \int\limits^2_0 {(2x^2+3)} \, dx$ . We will integrate that now: $\frac{1}{2}[ \frac{2x^3}{3}+3x]$ from 0 to 2. Filling in our upper and lower bounds we have $\frac{1}{2}[( \frac{2(2^3)}{3}+3(2))-0]$ which simplifies to $\frac{1}{2}( \frac{16}{3}+6)$ and $\frac{1}{2}( \frac{16}{3}+ \frac{18}{3})= \frac{1}{2}( \frac{34}{3})$ which is 17/3 or 5.667

7 0

3 years ago