Help ahhhh brainliest for 1st answer
2 answers:
You might be interested in
Answer:
a) P' = P
where t is step of 6 months
b) 7.7 years
c)1064.67 rabbits/year
Step-by-step explanation:
The differential equation describing the population growth is
Where t is the range of 6 months, or half of a year.
P(t) would have the form of
where is the initial population
After 6 month (t = 1), the population is doubled to 48
Therefore
where t is step of 6 months
b. We can solve for t to get how long it takes to get to a population of 1,000,000:
So it would take 15.35 * 0.5 = 7.7 years to reach 1000000
c.
We need to resolve for k if t is in the range of 1 year. In half of a year (t = 0.5), the population is 48
Therefore,
At the mid of the 3rd year, where t = 2.5, we can calculate P'
rabbits/year
Answer:
35.8
Step-by-step explanation:
= 358
We know that our answer can never be greater than 358 since the dividend
is 340.1 and the divisor is 9.5;
Also,
Both values are to one decimal places and we can use this to solve the problem;
9 can divide 340 in about 37 place with a remainder of 7,
So, it is appropriate to make the solution 35.8