Answer:
The answer to this question is given below in the explanation section.
Explanation:
The correct answer to this question is d- 346px.
The complete code of this example is given below:
<div>
style="margin:20px; border:solid 3px #888888;">
</div>
while the image width is 300px.
It is noted that the image width is 300px and the margin is 20 px.
Margin:20px means that image margin from four side is 20 px each.
So the width of dive from both side increase to 40 px and the image has 300 px, then total width becomes 340px. Now the border also has 3px of four sides of the image, then the width of the border becomes 6px.
so the total width of the div tag is 346 px.
In short, we can calculate the width of tag as below:
total width of div= width of image+ width of margin+ width of border
total width of dive= 300px+40px+6px
total width of div=346px.
Answer:
<em>Given Data:</em>
<em>myBytes BYTE 10h, 20h, 30h, 40h </em>
<em>myWords WORD 3 DUP(?), 2000h </em>
<em>myString BYTE "ABCDE"</em>
<em />
Based on the data that we are given we can conclude that:
(a). a. EAX = 1
b. EAX = 4
c. EAX = 4
d. EAX = 2
e. EAX = 4
f. EAX = 8
g. EAX = 5
Answer:
In the time complexity, the array-list can easily be accessible any type of element in the the given list in the fixed amount of time.
On the other hand, the linked list basically require that the list must be traversed from one position to another end position.
The Array-List can get to any component of the rundown in a similar measure of time if the file value is know, while the Linked-List requires the rundown to be crossed from one end or the other to arrive at a position.
num1 = float(input("Enter the first number: "))
num2 = float(input("Enter the second number: "))
operation = input("Which operation are you performing? (a/s/m/d) ")
if operation == "a":
print("{} + {} = {}".format(num1, num2, num1+num2))
elif operation == "s":
print("{} - {} = {}".format(num1, num2, num1-num2))
elif operation == "m":
print("{} * {} = {}".format(num1, num2, num1*num2))
elif operation == "d":
print("{} / {} = {}".format(num1, num2, num1/num2))
I hope this helps!
Answer:
1. TECHNOLOGY GRADE 9 TERM 3. In this chapter, you will revise the work you did on electrical systems and control
Explanation:Circuits can be found in just about every electronic device you ... An electric circuit is in many ways similar to your circulatory system
