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-BARSIC- [3]
3 years ago
7

Find the titles of courses in the Computer Science department that have 3 credits. Find the IDs of all students who were taught

by an instructor named Einstein; make sure there are no duplicates in the result. Find the highest salary of any instructor. Find all instructors earning the highest salary (there may be more than one with the same salary). Find the enrollment of each section that was offered in Fall 2017. Find the maximum enrollment, across all sections, in Fall 2017. Find the sections that had the maximum enrollment in Fall 2017. Increase the salary of each instructor in the Comp. Sci. department by 10%. Delete all courses that have never been offered (that is, do not occur in the section relation) Insert every student whose tot_cred attribute is greater than 100 as an instructor in the same department, with a salary of $10,000
Computers and Technology
1 answer:
Kay [80]3 years ago
4 0

Answer:

Explanation:

To solve this we break down the question and write the programme in steps as shown in the attachment

Download docx
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Is recursion ever required to solve a problem? What other approach can you use to solve a problem that is repetitive in nature?
Setler79 [48]

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No you can not tell that recursion is ever required to solve a problem.

Recursion is required when in the problem, the solution of the input depends on the solution of the subsets of the input.

Iteration is also another form of repetitive approach we follow to solve that kind of problems.

But the difference between recursion and iteration is :

  • In recursion we call the function repeatedly to return the result to next level.
  • In iteration certain bunch of instructions in a loop are executed until certain conditions met.

Explanation:

For example in the Fibonacci sequence problem, to find f_{n}, we need to compute f_{n-1} and f_{n-2} before that.

  • In case of recursion we just call the method Fibonacci(n) repeatedly only changing the parameter Fibonacci(n-1), that calculates the value and return it.

                           Fibonacci(n)

                           1. if(n==0 or n==1)

                           2.       return 1.

                           3.else

                           4.      return( Fibonacci(n-1)+Fibonacci(n-1) )

  • But in case of iteration we run a loop for i=2 to n, within which we add the value of current f_{i-1} and f_{i-2} to find the value of f_{i}

                           Fibonacci(n)

                           1. if(n<=2)

                           2.    result = 1

                           3.     else

                           4. result1 =1 and result2=1.

                           5.      {  result = result1 +result2.

                           6.         result1= result2.

                           7.         result2 = result.

                           8.      }

                           9.  output result.

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