Answer:
$367.87
Step-by-step explanation:
![P[(1 + r/100n)]^nt](https://tex.z-dn.net/?f=P%5B%281%20%2B%20r%2F100n%29%5D%5Ent)
![(2300)[(1 + (2.12)/100n)]^(52)(7)](https://tex.z-dn.net/?f=%282300%29%5B%281%20%2B%20%282.12%29%2F100n%29%5D%5E%2852%29%287%29)
Answer:
Option D Both students could be correct. Because the numbers are given in the original sequence, it is possible to find a common difference and common ratio between the successive terms.
Step-by-step explanation:
A geometric sequence has a common ratio. Here, that ratio would be 11/-5.5 = -2 if the sequence is geometric. That ratio would mean the next two terms are ...
11 × -2 = -22
-22 × -2 = 44
__
An arithmetic sequence has a common difference. Here, that difference would be 11 -(-5.5) = 16.5 if the sequence is arithmetic. That difference would mean the next two terms are ...
11 +16.5 = 27.5
27.5 + 16.5 = 44
__
These descriptions match those offered by the students, so both could be correct.
Answer: 3/2
Step-by-step explanation:
1= 2/2. 2/2 + 1/2 = 3/2
Answer:
Step-by-step explanation:
The formula for simple interest is expressed as
I = PRT/100
Where
P represents the principal
R represents interest rate
T represents time in years
I = interest after t years
Considering the first account,
T = 1 year
P = $10000
R = 5%
I = (10000 × 5 × 1)/100 = $500
The total amount = 10000 + 500 = $10500
he moved the total amount to a new account earning 6% interest. Therefore,
P = 10500
R = 6%
T = 1
I = (10500 × 6 × 1)/100 = $630
The amount of money that Marty would have at the end of the second year is
630 + 10500 = $11130
