A = l*w
6112 = l*28
l = 6112/28
l = 218.2857143
For a better understanding of the explanation provided here kindly go through the file attached.
Since, the weight attached is already at the lowest point at time, t=0, therefore, the equation will have a -9 as it's "amplitude" and it will be a Cosine function. This is because in cosine function, the function has the value of the amplitude at t=0.
Now, we know that the total angle in radians covered by a cosine in a given period is
and the period given in the question is t=3 seconds. Therefore, the angular velocity,
of the mentioned system will be:

Combining all the above information, we see that the equation which models the distance, d, of the weight from its equilibrium after t seconds will be:

Thus, Option B is the correct option. The attached diagram is the graph of the option B and we can see clearly that at t=3, the weight indeed returns to it's original position.
Answer:
(A)1/3
Step-by-step explanation:
probability of getting a 2 = 1/6
probability of getting a 6 = 1/6
so the probability of getting a 2 or a 6
=(probability of getting a 2+probability of getting a 6)
=(1/6+1/6)
=2*(1/6)
=1/3
Answer:
It's B
Step-by-step explanation:
The original equation is y - (y intercept)= slope(x-(x intercept))
Answer:
x = 4.14 y = -.7
Step-by-step explanation: