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2 years ago

Which is the x-intercept of the graph of the equation y=3x–9?

Mathematics

1 answer:

Vinvika [58]2 years ago

5 0

Y=3x-9
0=3x-9
-3x=-9
x=3
X-int = 3

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3 years ago

A die is tossed. fi d the odds against rolling a number greater than 1

anzhelika [568]

8.333333 reoccurring. 1 divided into 6 is 1.666667. Multiply by the remaining amount, 5? Idk

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3 years ago

Solve the equation and check your solution. (If all real numbers are solutions, enter REALS. If there is no solution, enter NO S

shepuryov [24]

Answer:

y=6/5 or 1 1/5

Step-by-step explanation:

combine like terms

5y+1= 10y-5

subtract 5y from both sides

1=5y-5

add 5 to both sides

6=5y

divide by 5 on both sides

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3 years ago

What is 3·3÷3·1²·5 and for any body who doesn't get it Ur not dumb lol

r-ruslan [8.4K]

I'll give you a hint. <u><em>This questions is about order of operations for pemdas. Its stand for: p-parenthesis, e-exponents, m-multiply, d-divide, a-add and s-subtract that came from left to right.</em></u>

First you had to calculate with exponents first.

$1^2=1*1=1$

$3*3/3*1*5$

Then you multiply and divide from left to right.

$3*3=9$

$9/3*1*5$

$3*1*5$

$3*5$

$=15$

Final answer: $\boxed{=15}$

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

7 0

3 years ago

Read 2 more answers

A. Show that the vector v = ai + bj is perpendicular to the line ax + by = c by establishing that the slope of v is the negative

pishuonlain [190]

Answer:

Part A:

$m_1m_2=-1$

$\frac{b}{a}(\frac{-a}{b})=-1\\-1=-1$

Hence proved that Vector= ai + bj is perpendicular to the line ax + by = c.

Part B:

Slope of vector = $\frac{b}{a}$

Step-by-step explanation:

Condition for perpendicular is:

$m_1m_2=-1$

Part A:

Consider the vector v = ai + bj

x component of vector=a

y component of vector=b

Slope of vector= $m_1=\frac{y}{x}=\frac{b}{a}$

Consider the line ax + by = c:

Rearranging the equation:

ax+by=c

by=c-ax

y= $\frac{-ax}{b}+\frac{c}{b}$

According to general equation of line: $y=mx+c$

Where m is the slope

In our case the slope of above line is:

$m_2=\frac{-a}{b}$

According to the condition of perpendicular:

$m_1m_2=-1$

$\frac{b}{a}(\frac{-a}{b})=-1\\-1=-1$

Hence proved that Vector= ai + bj is perpendicular to the line ax + by = c.

Part B:

Slope of vector is also calculated above.

Since the slope of vector is negative reciprocal of the slope of the given line:

According to equation of line ax + by = c

y= $\frac{-ax}{b}+\frac{c}{b}$

According to general equation of line: $y=mx+c$

Where m is the slope

Slope of given line=m= $\frac{-a}{b}$

negative reciprocal of the slope of the given line = $\frac{b}{a}$

Slope of vector = $\frac{b}{a}$

5 0

3 years ago