Answer:
0.0791
Step-by-step explanation:
Given that the probability of white eyes is 1/4 and the probability of red eyes is 3/4, for an individual fly.
Observations are independent
Let A be finding the white eyed fly and B
finding the red eyed fly
P(A) for any random trial= 0.25 and
P(B) = 0.75
Each trial is independent of the other
The probability that at least four flies have to be checked for eye color to observe a white-eyed fly
=Probability for I, II, III and Iv flies to have red eyes * Prob for 5th fly to have white eye
=
It's 26×10×10×10 because there are 26 possibilities (a-z) for the first letter and 10 possibilities (0-9) for each number. That makes the answer 26,000.
Answer:
You aren't asked which variable to solve for.
If we're solving for x then
4x = 12y -8
x = 3y - (8/4)
If we're solving for y
-12y = -4x -6
12y = 4x +6
y = (x/3) + (1/2)
Step-by-step explanation:
Answer:
-37/100
Step-by-step explanation:
Here, we want to write -0.37 as a quotient of integers
What we are saying is that we want to write it as a fraction of two numbers
That would be;
-0.37 = -37/100
C. x³-4x²-16x+24.
In order to solve this problem we have to use the product of the polynomials where each monomial of the first polynomial is multiplied by all the monomials that form the second polynomial. Afterwards, the similar monomials are added or subtracted.
Multiply the polynomials (x-6)(x²+2x-4)
Multiply eac monomial of the first polynomial by all the monimials of the second polynomial:
(x)(x²)+x(2x)-(x)(4) - (6)(x²) - (6)(2x) - (6)(-4)
x³+2x²-4x -6x²-12x+24
Ordering the similar monomials:
x³+(2x²-6x²)+(-4x - 12x)+24
Getting as result:
x³-4x²-16x+24
