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2 years ago

Which of the following is equivalent to the expression below? log 3-log 15

Mathematics

2 answers:

Nikitich [7]2 years ago

8 0

Answer:

$C. =log\frac{1}{5}$

Step-by-step explanation:

Formula =======================

<em>consider a and b two real numbers </em>

<em>where a > 0 and b > 0.</em>

$log\frac{a}{b} =loga-logb$

……………………………………………………………

log 3 − log 15

$=log\frac{3}{15}$

$=log\frac{3}{3\times 5}$

$=log\frac{1}{5}$

Lisa [10]2 years ago

6 0

Answer:

C log(1/5)

Step-by-step explanation:

log 3-log 15 = -log _10^(5)

log 5 = log _10^(5)

log (-12) = log _10^(-12)

log (1/5) = -log _10^(5)

log 12 = log _10^(12)

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a car left town A at 10:00 am and travelled towards town B at the average speed of 70 km/h. At the same time a truck left town B

Softa [21]

The important formula to this problem is $distance=rate(time)$ or $d=rt$

Now, the speed of the car is 70 km/h, and the speed of the truck is 50 km/h. It will take the two vehicles the same amount of time to meet since they both left at the same time. So, since distance equals rate times time, and t = time:

the distance of the car = 70t
the distance of the truck = 50t

Because they both left in opposite directions, and the towns are 420 kilometers apart, the equation for this would be

$70t+50t=420$

We now solve the equation.

$70t+50t=420 \\ 120t=420 \\ \frac{120t}{120}= \frac{420}{120} \\ t=3 \frac{1}{2}$

It will take the vehicles 3 and a half hours to meet. Since we're looking for the time, 3 and a half hours from 10:00 AM is 1:30 PM.

So, the car and the truck will pass each other at 1:30 PM.

8 0

3 years ago

1. Six units to the left of 3

trapecia [35]

Answer:

six uniys to left of 3 is= +2,+1,0,-1-2-3

three unit right of 15is= +16,+17, +18

Eight unit to the left of =-4,-5,-6,-8,-9,-10,-11,-12

seven units ti right of -5=-3,-2,-1,0+1,+2,+3,+4

8 0

2 years ago

Help! I'm a little stumped when it comes to variables in matrices. An explanation would be super rad!

iris [78.8K]

Answer:

Step-by-step explanation:

To find the determinant of a 3x3 matrix, you can use this method. (See picture.)

Start with the first number in the top row, and block off the row and column. A 2x2 matrix will be left. Find the determinant of this 2x2 matrix, and multiply it by the number in the top row.

Repeat for the other two numbers in the top row. Add the first result, subtract the second, and add the third.

det A = -2 [(3)(-5) − (a)(0)] − 2 [(0)(-5) − (a)(0)] + b [(0)(0) − (3)(0)]

det A = -2 (3)(-5) − 0 + 0

det A = 30

8 0

2 years ago

BC = x + 14, AB = x + 10, AC = 22

irinina [24]

$ab = x + 10 \\ bc = x + 14 \\ ac = 22 \\ (x + 10) + (x + 14) = 22 \\ x + x + 10 + 14 = 22 \\ 2x + 24 = 22 \\ 2x = 22 - 24 \\ 2x = - 2 \\ x = \frac{ -2}{2} \\ x = - 1$

4 0

2 years ago

irakobra [83]

X = 42 - 19, so A - x = 23

7 0

3 years ago

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