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Julli [10]
4 years ago
7

Find the number of 4-digit numbers that contain at least three odd digits.

Mathematics
1 answer:
Marrrta [24]4 years ago
6 0

Answer:

Total number = 3000

Step-by-step explanation:

Odd digit numbers = 1,3,5,7,9

Total no. of odd digit numbers = 5

Numbers which aren't odd = 0,2,4,6,8

Total no. which aren't odd = 5

For a 4 digit number.

If all Fours digits are odd:

Total numbers = 5×5×5×5 = 625

If first digit is not odd and last three digits are odd:

Total numbers = 4×5×5×5 = 500

(0 cannot be put at first digits place)

If second digit is not odd and rest three digits are odd:

Total numbers = 5×5×5×5 = 625

If third digit is not odd and rest three digits are odd:

Total numbers = 5×5×5×5 = 625

If fourth digit is not odd and rest three digits are odd:

Total numbers = 5×5×5×5 = 625

Add all of them we get:

Total number = 625+500+625+625+625 = 3000

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Dennis_Churaev [7]
  • <em>Answer:</em>

<em>x = - 2.5</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there !</em>

<em>4 - (2x + 4) = 5</em>

<em>4 - 2x - 4 = 5</em>

<em>- 2x = 5</em>

<em>2x = - 5</em>

<em>x = - 5 : 2</em>

<em>x = - 2.5</em>

<em>Good luck !</em>

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length of 1 half-life = 300 / 5.06 = 59.29 days
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