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2 years ago

Persevere with Problems The table shows the highway fuel economy of various popular vehicles.

Mathematics

1 answer:

Alja [10]2 years ago

5 0

The mean absolute deviation of highway fuel economy of various popular vehicles is 4.9

<h3>How to find mean absolute deviation?</h3>

Find the mean of the data set

= (38 + 48 + 25 + 35 + 33 + 37 + 32 + 34 + 23 + 30) / 10

= 335 / 10

= 33.5

Mean deviation of each set;

38 - 33.5 = 4.5

48 - 33.5 =14.5

25 - 33.5 = -8.5

35 - 33.5 = 1.5

33 - 33 .5 = -0.5

37 - 33.5 = 3.5

32 - 33.5 = -1.5

34 - 33.5 = 0.5

23 - 33.5 = -10.5

30 - 33.5 = -3.5

Absolute deviation of each value

|4.5| = 4.5

|14.5| = 14.5

|8.5| = 8.5

|1.5| = 1.5

|-0.5| = 0.5

|3.5| = 3.5

|-1.5| = 1.5

|0.5| = 0.5

|-10.5| = 10.5

|-3.5| = 3.5

Total absolute deviation = 4.5 + 14.5 + 8.5 + 1.5 + 0.5 + 3.5 + 1.5 + 0.5 + 10.5 + 3.5

= 49

Mean absolute deviation = Total absolute deviation / mean

= 49/10

= 4.9

Learn more about mean absolute deviation:

brainly.com/question/3998118

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Answer:

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Step-by-step explanation:

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4 years ago

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3 years ago

Line g passes through points (5, 9) and (3, 2). Line h passes through points (9, 10) and (2, 12). Are line g and line h parallel

icang [17]

For this case we find the slopes of each of the lines:

The g line passes through the following points:

$(x_ {1}, y_ {1}) :( 3,2)\\(x_ {2}, y_ {2}) :( 5,9)$

So, the slope is:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {9-2} {5-3} = \frac {7} {2}$

Line h passes through the following points:

$(x_ {1}, y_ {1}) :( 9,10)\\(x_ {2}, y_ {2}) :( 2,12)$

So, the slope is:

$m = \frac {y_ {2} -y_ {1}}{x_ {2} -x_ {1}} = \frac {12-10} {2-9} = \frac {2} {- 7} = - \frac {2} {7}$

By definition, if two lines are parallel then their slopes are equal. If the lines are perpendicular then the product of their slopes is -1.

It is observed that lines g and h are not parallel. We verify if they are perpendicular:

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Answer:

The lines are perpendicular.

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3 years ago

Sally needs 2/3 of a pound of potatoes. This is 1/3 of a pound more than 4/3 of the potatoes Sally has in her pantry

amid [387]

Lets assume, Sally has X pound of potatoes in her pantry.

So, 4/3 of the potatoes Sally has in her pantry = $\frac{4}{3}X$

Now, Sally needs 2/3 pound of potatoes and this 2/3 pound of potatoes is 1/3 pound more than that $\frac{4}{3}X$

So the representing equation will be:

$\frac{2}{3} = \frac{1}{3}+ \frac{4}{3}X$

$\frac{2}{3} - \frac{1}{3} = \frac{4}{3} X$ (subtracting $\frac{1}{3}$ from both sides)

$\frac{1}{3}= \frac{4}{3}X$

$1= 4X$ (multiplying both sides by 3)

$X =\frac{1}{4}$

So, Sally has $\frac{1}{4}$ pound of potatoes in her pantry.

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3 years ago