All categories

3 years ago

Please help me with this question.

Mathematics

1 answer:

Mumz [18]3 years ago

8 0

Answer:

Step-by-step explanatiobidvshzbxgsjsgsjGjmI don’t even know that

You might be interested in

Megan had some money in her wallet. Her mom gave her $38.25 to go shopping. Now Megan has fifty dollars. How much money did Mega

Ivenika [448]

Answer:

$11.75

Step-by-step explanation:

50-38.25=11.75

6 0

3 years ago

Read 2 more answers

Solve the two-step equation.<br> - 2/3 x - 21/4 = 27/4

Natasha_Volkova [10]

Answer:

x = -18

I hope this helps!

6 0

3 years ago

Read 2 more answers

Last week, there were 420 new subscribers to a Web site. This week, the number of new subscribers decreased by 5%. How many new

zlopas [31]

Answer:

x = 399 new subscribers

Step-by-step explanation:

Let 420 = 100%

x = 95%

420*95 = 100x

x = 420*95/100

x = 399 new subscribers

3 0

3 years ago

Solve y = log3243. anything helps!

9966 [12]

Y=3.51
You could just plug it into your calculator!

3 0

3 years ago

Use the following matrices, A, B, C and D to perform each operation.

Vinvika [58]

Step-by-step explanation:

$A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]$

$B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]$

$C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]$

$D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]$

$1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]$

$2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]$

$3.\\3C=3\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]=\left[\begin{array}{ccc}(3)(-2)&(3)(3)&(3)(1)\\(3)(-1)&(3)(0)&(3)(4)\end{array}\right]=\left[\begin{array}{ccc}-6&9&3\\-3&0&12\end{array}\right]$

$4.\\C\cdot D=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]\cdot\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]\\\\=\left[\begin{array}{ccc}(-2)(-2)+(3)(0)+(1)(3)&(-2)(3)+(3)(-2)+(1)(4)&(-2)(4)+(3)(1)+(1)(-1)\\(-1)(-2)+(0)(0)+(4)(3)&(-1)(3)+(0)(-2)+(4)(4)&(-1)(4)+(0)(1)+(4)(-1)\end{array}\right]\\=\left[\begin{array}{ccc}7&-8&-6\\14&13&-8\end{array}\right]$

$5.\\2D+3C\\\text{This operation can't be performed because the matrices}\\\text{ are of different dimensions.}$

6 0

3 years ago