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lesantik [10]
3 years ago
6

Given g(x) = -x + 3, solve for x when g(x) = -1.

Mathematics
1 answer:
cluponka [151]3 years ago
7 0

Answer:

4

Step-by-step explanation:

It's ok! This is simple. Simply plug in your given values. Since g(x) = -1, plug that into the equation.

g(x) = -x + 3

g(-1) = -(-1) + 3

=1+3

=4

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Step-by-step explanation:

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3 years ago
Select all that apply
Anastaziya [24]

Answer:

<h2>Third option</h2>

\log _{10}\left(20x^5\right)-1\\

Step-by-step explanation:

5\log _{10}\left(x\right)+\log _{10}\left(20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\\\quad \:a\log _c\left(b\right)=\log _c\left(b^a\right)\\\\5\log _{10}\left(x\right)=\log _{10}\left(x^5\right)\\\\=\log _{10}\left(x^5\right)+\log _{10}\left(20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\\\quad \log _c\left(a\right)+\log _c\left(b\right)=\log _c\left(ab\right)\\\\\log _{10}\left(x^5\right)+\log _{10}\left(20\right)=\log _{10}\left(20x^5\right)\\\\

=\log _{10}\left(x^5\cdot \:20\right)-\log _{10}\left(10\right)\\\\\mathrm{Apply\:log\:rule}:\quad \log _a\left(a\right)=1\\\\=\log _{10}\left(20x^5\right)-1

5 0
3 years ago
Read 2 more answers
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balandron [24]

Answer:

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Step-by-step explanation:

If you look at the information it gives you, you can see it says 12 quizzes in 3 weeks and she needs 24 quizzes. So every 3 weeks she does 12 quizzes, and if you add 12 and 12 you get 6 weeks.

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