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drek231 [11]
2 years ago
13

Does anyone know the answer to this problem?

Mathematics
1 answer:
Mariana [72]2 years ago
6 0

The regression equation is y = 16.585x - 639.769 and the linear correlation coefficient indicates a strong linear relationship

<h3>How to determine the regression equation?</h3>

To do this, we make use of a statistical calculator;

Using the statistical calculator, we have the following summary:

  • Sum of X = 554
  • Sum of Y = 4070
  • Mean X = 69.25
  • Mean Y = 508.75
  • Sum of squares (SSX) = 725.5
  • Sum of products (SP) = 12032.5
  • Correlation coefficient, r = 0.9768

The regression equation is

ŷ = bx + a

Where:

b = SP/SSX = 12032.5/725.5 = 16.58511

a = MY - bMX = 508.75 - (16.59*69.25) = -639.76912

Hence, the regression equation is y = 16.585x - 639.769

<h3>The number of cans sold at 90 degrees F</h3>

This means that"

x = 90

So, we have:

y = 16.585 * 90 - 639.769

Evaluate

y = 852.881

Approximate

y = 853

Hence, 853 cans were sold at 90 degrees F

<h3>The linear correlation coefficient</h3>

In (a), we have:

r = 0.9768

This means that the linear correlation coefficient is 0.9768

<h3>The conclusion</h3>

We have:

r = 0.9768

The above value is closer to 1 because

|r| > 0.9

i.e.

0.9768 > 0.9

Hence, the linear correlation coefficient indicates a strong linear relationship

Read more about regression at:

brainly.com/question/17844286

#SPJ1

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aalyn [17]
0 Solutions in the system
4 0
3 years ago
3r²-6-3r=0 i have to use quadratic formula but i dont get how to imput it
yKpoI14uk [10]

Answer:

r = 2

r = -1

Step-by-step explanation:

So first, we need to get this is order of: ax^2 + bx + c

3r^2 - 6 - 3r

3^2 - 3r - 6

the formula is: -b ± √b^2 -4ac/2a

"ax^2 + bx + c" = "3^2 - 3r - 6"

a = 3

b = -3

c = -6

-b ± √b^2 -4ac/2a

-(-3) ± √(-3)^2 -4(3)(-6)/2(3)

3 ± √9 + (-12)(-6)/6

3 ± √9 + (72)/6

3 ± √9 + 72/6

3 ± √81/6

3 ± 9/6

3 - 9/6

-6/6

-1 = r

3 + 9/6

12/6

2 = r

Formula down below --

                                      |

                                     V

4 0
3 years ago
5. A pole has to be erected at a point on the boundary of a circular park of diameter 13 metres in
lesya [120]

Answer:

Thus, it is possible to erect a pole at a point p on the boundary of the park at distances 5m and 12m respectively from gates B and A.

Step-by-step explanation:

Let P be the required location of pole .

A and B are the two gates.

Let the distance of pole at p from gate be 'x' meters

i.e. PB = x m

•°• AP = (x + 7)m and AB = 13 m

•°• AP² + BP² = AB² => (x +7)² + x =13²

Rejecting x =-12, we get x = 5

•°• PB = 5m

and

AP = 12m

(I hope this helped :)

4 0
3 years ago
PLEASE HELP!!! Write an absolute value equation representing all numbers x whose distance from 0 is 10 units.​
tangare [24]
X would be the absolute value of 10 or -10 since they both are 10 units from 0 so it can be x=l10l or x=l-10l, they both equal 10
5 0
4 years ago
Find the side in of point a to point c
vladimir1956 [14]

Step 1:

Calculate the measure of angle ∠ABC

\angle DBC+\angle ABC=180(\text{ sum of angles on a straight line)}\angle ABC=65^0\begin{gathered} \angle DBC+\angle ABC=180 \\ \angle DBC+65^0=180^0 \\ \angle DBC=180^0-65^0 \\ \angle DBC=115^0 \end{gathered}

From the triangle in the question,

a=10\operatorname{km},c=15\operatorname{km},B=115^0

Step 2:

Calculate the value of AB using the cosine rule below

b^2=a^2+c^2-2\times a\times c\times\cos B

By substituting the values, we will have

\begin{gathered} b^2=a^2+c^2-2\times a\times c\times\cos B \\ b^2=10^2+15^2-2\times10\times15\times\cos 115^0 \\ b^2=100+225-300\times(-0.4226) \\ b^2=325+126.78 \\ b^2=451.78 \\ \text{Square root both sides} \\ \sqrt[]{b^2}=\sqrt[]{451.78} \\ b=21.26\operatorname{km} \end{gathered}

Hence,

The distance of point A to point C is = 21.26km

3 0
1 year ago
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