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MrMuchimi
3 years ago
10

PLEASE HELP!!! Write an absolute value equation representing all numbers x whose distance from 0 is 10 units.​

Mathematics
1 answer:
tangare [24]3 years ago
5 0
X would be the absolute value of 10 or -10 since they both are 10 units from 0 so it can be x=l10l or x=l-10l, they both equal 10
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A roll of wire has 51 inches of wire. If each bracelet requires 7.2 inches of wire, estimate the number of bracelets that can be
sergeinik [125]

Answer:

7

Step-by-step explanation:

51 ÷ 7.2 is about 7.08 continued but you can't make .08 of a braclet so it's just 7

8 0
3 years ago
Which statement describes the graph of the system of equations below?
insens350 [35]
1.5x + 0.2y = 2.68....multiply by 0.3
1.6x + 0.3y = 2.98...multiply by - 0.2
------------------------
0.45x + 0.06y = 0.804 (result of multiplying by 0.3)
- 0.32x - 0.06y = - 0.596 (result of multiplying by - 0.2)
----------------------add
0.13x = 0.208
x = 0.208/0.13
x = 1.6

1.5x + 0.2y = 2.68
1.5(1.6) + 0.2y = 2.68
2.4 + 0.2y = 2.68
0.2y = 2.68 - 2.4
0.2y = 0.28
y = 0.28/0.2
y = 1.4

solution (they intersect at) (1.6,1.4)
8 0
3 years ago
Read 2 more answers
The formula y = mx + b is called the slope-intercept form of a line. Solve this formula for m
Evgesh-ka [11]

Answer:

m = \frac{y-b}{x}

Step-by-step explanation:

Given

y = mx + b ( subtract b from both sides )

y - b = mx ( divide both sides by x )

\frac{y-b}{x} = m

3 0
3 years ago
Dafjjfdsfrdddddddd DISJFJIASJIFAJIFAIJIJASJDIASIJDJAISDJAIS
photoshop1234 [79]

Answer:

What?

Step-by-step explanation:

3 0
3 years ago
Which statement describes the inverse of m(x) = x^2 – 17x?
DochEvi [55]

Given:

The function is

m(x)=x^2-17x

To find:

The inverse of the given function.

Solution:

We have,

m(x)=x^2-17x

Substitute m(x)=y.

y=x^2-17x

Interchange x and y.

x=y^2-17y

Add square of half of coefficient of y , i.e., \left(\dfrac{-17}{2}\right)^2 on both sides,

x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2

x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2        [\because (a-b)^2=a^2-2ab+b^2]

Taking square root on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}

Add \dfrac{17}{2} on both sides.

\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y

Substitute y=m^{-1}(x).

m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}

We know that, negative term inside the root is not real number. So,

x+\left(\dfrac{17}{2}\right)^2\geq 0

x\geq -\left(\dfrac{17}{2}\right)^2

Therefore, the restricted domain is x\geq -\left(\dfrac{17}{2}\right)^2 and the inverse function is m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}.

Hence, option D is correct.

Note: In all the options square of \dfrac{17}{2} is missing in restricted domain.

7 0
3 years ago
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