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Tamiku [17]
1 year ago
11

Please help i don't understand!

Mathematics
1 answer:
ladessa [460]1 year ago
7 0

Answer:(2x-5)(x+10)

Step-by-step explanation:

picture below

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The area of a square is increasing at the constant rate of 16sq.ft./min. When the perimeter of the square is 36ft, how fast is t
bixtya [17]

Answer:

The perimeter of square is increasing by 3.76ft/min and then by 3.4 ft/min.

Step-by-step explanation:

Given that area of square is increasing at a rate of 16 sq ft/min.

Given that final perimeter is 36ft

Perimeter of a square = 4 \times side = 36

So, side, a' = 9 ft

We know that area of a square is given by the formula:

A = side^2 = a^2 (If we let side = a units)

Change in area =

a'^2 - a^2\\\Rightarrow 9^2 - a^2 = 16\\\Rightarrow 81 - 16 = a^2\\\Rightarrow a = 8.06\ ft

So, side got changed from 8.06ft to 9 ft.

So, perimeter when side was 8.06 ft:

4 \times 8.06 = 32.24\ ft

Hence, increase in the perimeter when perimeter is 36 ft is = 36 - 32.24 = 3.76 ft

For finding Next increase:

area gets changed from 81 sq ft to 81+16 = 97 sq ft

So, new side = \sqrt{97} ft = 9.85 ft

Next increase in perimeter = 4 (New side - Old side)

= 4 (9.85 - 9)

= 3.4 ft/min

6 0
3 years ago
What type of transformation can be defined as turning a figure about a fixed point with no change to the size or shape of the fi
Mekhanik [1.2K]
The type of transformation that turns a figure without changing the size or the shape of the figure is called a ROTATION. An example is given in the diagram below. The triangle has been rotated 90° about the origin

3 0
3 years ago
Y=-3x^2-6x+24
Lera25 [3.4K]
The x-intercept is the point at which the function intersects the x-axis.
For any point on the x-axis, y = 0. Thus we can plug in 0 for y and solve for x.

y=-3x^2-6x+24 \\ 0=-3x^2-6x+24

Let's split the middle on this quadratic.
To do this we need to find two numbers that add to equal -6 and multiply to equal -72. (-3 times 24)
Consider ways to multiply to get 72.
72 = 36 ×2...that's not going to work.
72 = 24 × 3
72 = 18 × 4
72 = 12 × 6...and 12 minus 6 is 6!
Let's add our signs; our numbers are -12 and 6.
Now, split the middle and factor.

0=-3x^2-12x+6x+24\\0=-3x(x+4)+6(x+4)\\0=(-3x+6)(x+4)

Now you should know that anything multiplied by zero is zero.
So any value that makes one of those factors equal zero is an x-intercept.
Solve each of these equations.

-3x+6 = 0
-3x = -6
x = 2

x+4 = 0
x = -4

Oh, and since all parabolas (graphs of quadratics) are symmetrical, our axis of symmetry will be the average between the two, which is x=-1.

Now for our y-intercepts. For any points on the y-axis, x=0, so if we plug in 0 for x and solve for y we'll get our y-intercept.

y = -3×0² - 6×0 + 24
y = 0 - 0 + 24
y = 24

What about our vertex? Well, we know it's going to line up with the axis of symmetry, so let's just plug in -1 for x.

y = -3×-1² - 6×-1 + 24
y = -3×1 -6×-1 + 24
y = -3 + 6 + 24
y = 27

Thus the vertex is (-1, 27)

The y value is not going to exceed 27, as this is a decreasing quadratic, (we already know y=24 is a possibilty) and this equation goes downwards infinitely, so our range is (-∞, 27)

As for x, well, it's sort of the input for our equation, meaning it can be whatever we want it to be. Thus the domain is (-∞, ∞)




3 0
3 years ago
Quadrilateral DUCKDUCKD, U, C, K is inscribed in circle OOO. What is the measure of \angle K∠Kangle, K?
N76 [4]

Answer:

Measure of ∠K=180-∠U

Or

Measure of ∠K=1/2m(arc DUC)

Step-by-step explanation:

Given:

DUCK quadrilateral inscribed in circle with center O

To Find:

Measure angle K

Solution:

Here the Quadrilateral in inscribed in a circle with center O named as DUCK

So angle K and  U are opposite to each other

We know that the angle of Quadrilateral inscribed in a circle are supplemenatry angles

Hence

∠U+∠K=180

Or The ∠K=1/2*m∠arc(DUC).

Hence depending on the given value for arc measure or angle of quadrilateral we calculate the angle K

5 0
3 years ago
Read 2 more answers
8 m<br> 3 m<br> 5 m<br> 2 m<br> 3 m<br> 9 m<br> 8 m
Andrew [12]

Answer:

this makes no sense at all, what's the question?

5 0
2 years ago
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