3 years ago

I need help nowwww pleaseeee it anyone can see this

Mathematics

1 answer:

dalvyx [7]3 years ago

7 0

If you could give me the question maybe I can answer it!!

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What is the degree of <br> 6x^5 – 4x^2 + 2x^2 - 3 + x?<br> A. 3<br> B. 5<br> C. 6<br> D.2

laila [671]

Hello!

<h2>Answer:</h2>

$\boxed{ \bf The~degree~of~the~polynomial~is~B.~5}$

___________________________________________

<h2>Explanation: </h2>

The term with the greatest exponent determines the degree of the polynomial.

Let's list all the terms:

$6x^{5}$

-4x²
2x²
-3
x

Out of all of these terms, the first one has the greatest exponent (5).

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3 years ago

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Mr Stephens will need to haul in 58.4 tons o move all of the rocks

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4 years ago

Describe the graph of the function.

gayaneshka [121]

Answer:

The answer is option 1.

Step-by-step explanation:

Axis of symmetry means the middle x-coordinates of the parabola. So in order to find the x value, you have to find the TP which is Turning Point by using Completing the Square :

${(x + \frac{b}{2} )}^{2} - {( \frac{b}{2} )}^{2} + c = 0$

Let y = 0,

$2{x}^{2} + 12x - 15 = 0$

$2( {x}^{2} + 6x - \frac{15}{2} ) = 0$

${( {x + \frac{6}{2}) }^{2} - ( { \frac{6}{2} )}^{2} - \frac{15}{2} } = 0$

$( {x + 3)}^{2} - {(3)}^{2} - \frac{15}{2} = 0$

$( {x + 3)}^{2} - 9 - \frac{15}{2} = 0$

$(x { + 3)}^{2} - \frac{33}{2} = 0$

$2(x { + 3)}^{2} - 33 = 0$

Next, you have to solve the x value :

x + 3 = 0

x = -3

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3 years ago

According to the Rational Root Theorem, which function has the same set of potential rational roots as the function g(x) = 3x5 –

BaLLatris [955]

The function that has the same set of potential rational roots is
<span>4(3x5-2x4+9x3-x2+12). If you see it from your options I know this is the one who is closer to the same set you are looking for. </span>

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4 years ago

Read 2 more answers

Last saturday, marissa walked her dog 1 1/2 miles. Sally walked her dog 2 times far. How many miles total did both girls walk th

andriy [413]

Answer:

4.5 miles

Step-by-step explanation:

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3 years ago