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Angelina_Jolie [31]
3 years ago
11

Question 8 of 10

Biology
2 answers:
jonny [76]3 years ago
5 0

The purpose of control group 2 is to determine if the new drug was a possible method for getting well, i.e., option B.

<h3>What is way of testing medicines?</h3>

In a laboratory, drugs are first subjected to non-human tests. These laboratory tests are performed to determine a level of safety.

The results of these tests are then submitted to the United States Food and Drug Administration (FDA), which determines whether the treatment is safe enough to be studied in human volunteers.

There are various phases involving discovery, clinical trial, review, and safety monitoring.

The purpose of control group 2 is to determine if the new drug was a possible method for getting well

Thus, the correct option is B.

For more details regarding drug testing, visit:

brainly.com/question/11332268

#SPJ1

anzhelika [568]3 years ago
4 0

The goal of control group 2 is to ascertain whether the novel medicine, or option B, was a potential cure.

<h3>How are medications tested?</h3>

Drugs are initially tested on animals in a laboratory. To establish a level of safety, these laboratory tests are conducted.

Following the completion of these testing, the Food and Drug Administration (FDA) of the United States makes a decision regarding whether the treatment is secure enough to be tested on human volunteers.

Discovery, clinical trial, evaluation, and safety monitoring are some of the phases.

Control group 2's goal is to ascertain whether the new medicine was a potential cure.

For more details regarding drug testing, visit:

brainly.com/question/11332268

#SPJ1

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Yanka [14]

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See the answer below

Explanation:

<em>Recall that the law of dilution states that the number of moles before dilution must be equal to the number of moles after dilution.</em>

Mathematically,

     molarity x number of moles before dilution = molarity x number of moles after dilution.

For solution A: final molarity = 3 mM, final volume = 2mL, initial molarity of KMnO4 = 10 mM

Applying the equation:

    10 x initial volume = 3 x 2

        initial volume = 6/10 = 0.6

<u>Hence, Tube A should be made with 0.6 mL of 10 mM KMnO4 stock and  1.4 mL of distilled water to give a solution of 2 mL 3 mM KMnO4.</u>

For solution B:final molarity = 8 mM, final volume = 2 mL, initial molarity = 10 mM

    10 x initial volume = 8 x 2

       initial volume = 16/10 = 1.6

<u>Hence, Tube B should be made with 1.6 mL of 10 mM KMnO4 stock and 0.4 mL of distilled water to give a solution of 2 mL 8mM KMnO4. </u>

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