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nordsb [41]
2 years ago
12

14

Mathematics
1 answer:
Damm [24]2 years ago
8 0

-n=2-7

-n=5

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What polynomial expression will make this equation true?<br> (3x +2) - ? = (6x+7)
Angelina_Jolie [31]
The answer is ?-36 I hope this is help
7 0
3 years ago
6-2/3(x+5)=4x solve for x
laiz [17]

Answer:

3x^2+15x-1=0

Step-by-step explanation:

4/(3x+15)=4x

4=12x^2+60x

12x^2+60x-4=0

3x^2+15x-1=0

Please solve after that, I cannot do everything for you

5 0
2 years ago
#16 and #19 only <br> Please answer both as soon as possible.
Vlad1618 [11]

Answer:

1. it is not a direct variation because the value <em>k</em> is not kept throughout the ordered pairs

2. -a^5 - 2a³ + 2a², leading coefficient is -1

Step-by-step explanation:

1. to find the direct variation, we will use y/x = k with k representing our constant throughout the chart. if every value is equal to k, it is a direct variation

for this problem we will assume that the cup sizes are x and the cost is y

so the ordered pairs are (8, 0.90), (12, 1.35), (16, 1.80), and (24, 2.25)

.90/8 = 0.1125 <-- this is our <em>k</em> value for which every result has to be equal to

1.35/12 = 0.1125

1.80/12 = 0.1125

2.25/24 = 0.09375

since the value <em>k</em> was not kept throughout the ordered pairs, this is not a direct variation

2. the standard form of a polynomial is the exponents in descending order.

we have the following polynomial: 2a² - a^5 -2a³

to write it in standard form, we will go in descending order of the exponents. the largest exponent being first

-a^5 - 2a³ + 2a²

the leading coefficient of the polynomial is -1, as there is a negative sign in front of the newly formed polynomial

4 0
3 years ago
Hey so im also looking for the first answer and the choices were “ is not “ and “ is “
dexar [7]

so the investigator found the skid marks were 75 feet long hmmm what speed will that be?

s=\sqrt{30fd}~~ \begin{cases} f=\stackrel{friction}{factor}\\ d=\stackrel{skid}{feet}\\[-0.5em] \hrulefill\\ f=\stackrel{dry~day}{0.7}\\ d=75 \end{cases}\implies s=\sqrt{30(0.7)(75)}\implies s\approx 39.69~\frac{m}{h}

nope, the analysis shows that Charlie was going faster than 35 m/h.

now, assuming Charlie was indeed going at 35 m/h, then his skid marks would have been

s=\sqrt{30fd}~~ \begin{cases} f=\stackrel{friction}{factor}\\ d=\stackrel{skid}{feet}\\[-0.5em] \hrulefill\\ f=\stackrel{dry~day}{0.7}\\ s=35 \end{cases}\implies 35=\sqrt{30(0.7)d} \\\\\\ 35^2=30(0.7)d\implies \cfrac{35^2}{30(0.7)}=d\implies 58~ft\approx d

4 0
3 years ago
the morning tempature was -7C. By noon the tempature was 8C. how many degrees has the tampature risen
ddd [48]
It has risen 15 degrees .....
7 0
3 years ago
Read 2 more answers
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