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weeeeeb [17]
2 years ago
14

Help me out.

Mathematics
1 answer:
alexandr1967 [171]2 years ago
5 0

Answer:

5x + 10

5(x + 2)

Step-by-step explanation:

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Solve the system: x' = (2 4 -1 6)x
sertanlavr [38]

Answer:

x=e^{8t}+c

Step-by-step explanation:

we have given x'=(24-16)x=8x

x' denotes the differenation

\frac{dx}{dt}=8x  differentiation is performed with respect to t

by variable separable method we can write  

\frac{dx}{x}=8dt

on integrating both side

lnx=8t+c

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6 0
3 years ago
100 POINTS!!! PLEASE I NEED HELP DUE TODAY!!!!
Volgvan

Using weighed averages, it is found that:

  1. The final grade is 91.
  2. The final grade is 66.8.
  3. The higher grade would be 79.55, with the second grading scheme.
  4. On average, she sold $48,280 per day.
  5. On average, she makes $12.5 per hour.

---------------------------------------

To find the weighed average, we multiply each value by it's weight.

---------------------------------------

Question 1:

  • Grade of 91, with a weight of 67%.
  • Grade of 91, with a weight of 33%.

Thus:

F = 91\times0.67 + 91\times0.33 = 91

The final grade is 91.

---------------------------------------

Question 2:

  • Grade of 83, with a weight of 40%(highest grade).
  • Grade of 60, with a weight of 30%.
  • Grade of 52, with a weight of 30%.

Thus:

F = 83\times0.4 + 60\times0.3 + 52\times0.3 = 66.8

The final grade is 66.8.

---------------------------------------

Question 3:

With teacher 1:

  • 75 with a weight of 25%.
  • 80 with a weight of 10%.
  • 85 with a weight of 40%.
  • 62 with a grade of 25%.

Thus:

F_1 = 75\times0.25 + 80\times0.1 + 85\times0.4 + 62\times0.25 = 76.25

---------------------------------------

With teacher 2:

  • 75 with a weight of 15%.
  • 80 with a weight of 10%.
  • 85 with a weight of 60%.
  • 62 with a weight of 15%.

Thus:

F_2 = 75\times0.15 + 80\times0.1 + 85\times0.6 + 62\times0.15 = 79.55

The higher grade would be 79.55, with the second grading scheme.

---------------------------------------

Question 4:

  • Average of $36,432, with a weight of \frac{3}{3+10} = \frac{3}{13}
  • Average of $51,834, with a weight of \frac{10}{13}

Thus:

A = 36432\frac{3}{13} + 51834\frac{10}{13} = \frac{36432\times3 + 51834\times10}{13} = 48280

On average, she sold $48,280 per day.

---------------------------------------

Question 5:

  • Average of $14.84, with a weight of \frac{6}{6+8} = \frac{6}{14} = \frac{3}{7}
  • Average of $10.76, with a weight of \frac{4}{7}

Thus:

A = 14.84\frac{3}{7} + 10.76\frac{4}{7} = \frac{14.84\times3 + 10.76\times4}{7} = 12.5

On average, she makes $12.5 per hour.

A similar problem is given at brainly.com/question/24398353

5 0
3 years ago
HELP!! ANSWER QUICK!!:)))
Lapatulllka [165]

Answer:

bleh bleh bleh hehebeiejhsievdudveusvsgzyvehs

4 0
2 years ago
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