All categories

1 year ago

Angles A and B are complementary. If sin A = 5x + 9 and cos B = 3x + 21, what is the value of x? (1 point) 2 6 15 39

Mathematics

1 answer:

nadezda [96]1 year ago

7 0

The value of x is 6.

<h3>What are complementary?</h3>

Complementary angles are angles that sum up to 90°.

Analysis:

For angles A and B, to be complementary, the sine of angle A must be equal to the cosine of angle B.

sin A = cos B

5X+9 = 3x+21

5x - 3x = 21 - 9

2x = 12

x = 6

In conclusion, the value of x to make angles A and B complementary is 6.

Learn more about complementary angles: brainly.com/question/98924

#SPJ1

You might be interested in

Log5(5)=x<br> solve for x

Ilia_Sergeevich [38]

Answer:

x = 1

Step-by-step explanation:

Using the rule of logarithms

$log_{b}$ b = 1

That is the logarithm of a number to the same base is 1

Given

$log_{5}$ 5 = x , hence x = 1

6 0

3 years ago

Read 2 more answers

What is the simplest form of 4a + 8b/12<br> Step by step pls

shutvik [7]

Answer:

4a + 2b/3

Step-by-step explanation:

focus on 8b/12 first:

factor 8b/12 by 4 ---> 8b/12 = 4(2)b/4(3) ----> cancel 4 in the denominator and the nominator ---> 8b/12 = 4(2)b/4(3) = 2b/3

then, go back to 4a:

4a is in its simplest form, it can't be factor

therefore, plus 4a and 2b/3 = 4a + 2b/3

5 0

3 years ago

Simplify i^41 (please help me)

ira [324]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Write an equation that has a graph with the shape of y = x^2, but shifted left 3 units.

svetoff [14.1K]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf % template detailing
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\$

$\bf \bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

now, with that template in mind, let's see

$\bf y=x^2\implies 
\begin{array}{llll}
y=(&1x&-0)^2\\
&B&C
\end{array}$

so, just change C to +3, thus C/B is 3/1

6 0

3 years ago

Help with 21 would be much appreciated.

umka2103 [35]

Answer:

$\large\boxed{x=2\sqrt{21}\ and\ y=4\sqrt3}$