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Fiesta28 [93]
3 years ago
13

Simplify i^41 (please help me)

Mathematics
2 answers:
ira [324]3 years ago
8 0

Answer:

i

Step-by-step explanation:

SOVA2 [1]3 years ago
8 0

Answer:  Choice A) i

====================================================

Explanation:

Let's look at the pattern of powers of i

  • i^0 = 1
  • i^1 = i
  • i^2 = (sqrt(-1))^2 -1
  • i^3 = i*i^2 = i*(-1) = -i
  • i^4 = (i^2)^2 = (-1)^2 = 1

We loop back to 1, and the process starts all over again. The cycle is 4 units long. Ie, the pattern repeats every 4 terms.

What this means is that we can use remainders to quickly figure out something like i^41 without having to use a calculator or tons of paper.

Dividing 41/4 leads to a quotient of 10 and a remainder of 1. We only care about the remainder. The remainder 1 means i^41 = i^1 = i

Note how 41 and 1 lead to the same remainder when we divide by 4.

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