Graph (x-2)^2 + (y-1)^2 = 9
1 answer:
Step-by-step explanation:
Given the following question:
First thing we need to keep in mind is the fact that this graph is indeed a circle. We know this because we are adding two cubic roots to each other which makes the graph a circle. We know the two separate functions are cubic roots because they each have an exponent of two. Not only is this function whose graph is a circle, but the midpoint of this circle is (2,2).
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I guess there's a mistake in the question.
Answer:
Ques 1:
Let us consider the system of equations,
and
It is known that 'The intersection points of the graphs of the system of equations are the solutions of the system of equations'.
So, after plotting the given graphs, we see that from the first graph,
The only intersection point is (1,1).
Thus, the solution of the system is x= 1 and y= 1.
Ques 2:
We have the functions, f(x)= 2x+1 and g(x)= 2x^2+1.
Plotting the graphs of both the functions is shown by graph 2, we see that,
The intersection points are (0,1) and (1,3)
Hence, the function have equal values only at x= 0 and x= 1 but not at x= 3.
